Answer:
375 ft
Step-by-step explanation:
The increase in height in the 1st second is 103 ft. In the 2nd second, it is 192-103 = 89 ft, a decrease of 14 ft. In the next three seconds, the increases in height can be expected to be ...
89 -14 = 75 ft
75 -14 = 61 ft
61 -14 = 47 ft
for a total increase in height over those 3 seconds of ...
75 + 61 + 47 = 183 ft
Then the height after 5 seconds in the air is ...
192 ft + 183 ft = 375 ft
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You can model the height function with the quadratic equation ...
h(t) = at^2 +bt
We need to find the values of "a" and "b", which we can do by substituting the given data point values. The given data is ...
h(1) = a + b = 103
h(2) = 4a + 2b = 192
Subtracting twice the first equation from the second, we get
(4a +2b) -2(a +b) = (192) -2(103)
2a = -14 . . . . . simplify
a = -7 . . . . . . . divide by 2
b = 103 -a = 110 . . . . find b using the first equation
Then the quadratic model of height is ...
h(t) = -7t^2 +110t
and the height at 5 seconds is ...
h(5) = -7·25 +110·5 = 375 . . . feet
