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Sloan [31]
2 years ago
6

Kasey has been mowing lawns to save up money for a concert. He earns $15 per hour and needs at least $90 to go to the concert. H

ow many hours should he mow? Write an inequality (with variable) to solve it.
Mathematics
1 answer:
GREYUIT [131]2 years ago
4 0

Answer:

he makes 15 dollars in an hr, so find how much 15 dollars goes into 90. 90 divide 15 = 6. therfore, kasey needs to work for 6 hours to make 90 dollars

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Help please!!
alukav5142 [94]
The answer is (1,11).
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%20-%20%20%5Cfrac%7B4%7D%7B10%7D%20%20%3D%20" id="TexFormula1" titl
rusak2 [61]

Answer:

8/30 (Simplified answer: 4/15)

Step-by-step explanation:

Find common denominators. Note the what you do to the denominator, you do to the numerator.

Multiply 10 to both the denominator & numerator of 2/3, and multiply 3 to both the denominator & numerator of 4/10

(10/10)(2/3) - (3/3)(4/10)

Simplify.

(20/30) - (12/30)

Simplify. Combine the terms

(20/30) - (12/30) = (20 - 12)/30 = 8/30

Simplify the fraction

(8/30)/(2/2) = 4/15

~

6 0
2 years ago
What is the total number of 17 year olds whos height is 74 inches or less
stira [4]

Answer:

2

Step-by-step explanation:

there is 2 dots along the line of 17 before 74

hope this helps :)

6 0
3 years ago
The mean age of swimers for all of these teams is 10. what does a large mad tell you.eade help​
aev [14]
Answer: Larger the MAD tells us that the ages of swimmer are far from the mean age. Thus means is not a relevant indicator for the data.
Step-by-step explanation:
We know that the mean absolute deviation (MAD) helps to know whether the mean of a data is a worthy indicator for the data values .
The larger the MAD tells us the values are spread out far from the mean .
Also, larger the MAD makes the mean less worthy as an indicator of the data elements within the data set.
8 0
3 years ago
What is the pattern of odd and even products in each row
andrew11 [14]
There isn't a picture of a pattern to go by.
5 0
2 years ago
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