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ratelena [41]
3 years ago
5

Fifty eight students were surveyed about how frequently they text during lunch. The results are summarized below. Which statemen

ts are true about the data for the number of texts sent during lunch? Select all that apply.
Chart: (the numbers below are next to each other)
number of texts- 0,2,3,5,6,8,9,11,14
number of students-3,4,2,5,3,8,6,15,12
Box Plot:
lunch texts-0,6,9,11,14
The Choices:
The median number of texts sent is 9
1) The IQR for the data is 6
2) The third quartile is 11
3) The data is skewed to the left
4) The mean of the data will be greater than the median
5) The lowest 25% of texts sent at lunch is between 0 and 6
6) The middle 50% of texts sent at lunch is between 6 and 9
Need help please and thanks :((
Mathematics
1 answer:
umka2103 [35]3 years ago
4 0

Answer:The median number is 9 , Q3 is 11, data is skewed left, lowest 25%

Step-by-step explanation:

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rewona [7]

\text{L.H.S}\\\\=\begin{vmatrix} 1 & bc& b+c\\ 1 & ca& c+a\\ 1 &ab&a+b\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & bc& b+c-(a+b+c)\\ 1 & ca& c+a-(a+b+c)\\ 1 &ab&a+b-(a+b+c)\end{vmatrix}~~~~~~~~~~~~~~~;c_3\rightarrow c_3 -(a+b+c)c_1\\\\\\=\begin{vmatrix} 1 & bc& -a\\ 1 & ca& -b\\ 1 &ab&-c\end{vmatrix}\\\\\\=\dfrac 1{abc}\begin{vmatrix} a & abc& -a^2\\ b & abc& -b^2\\ c &abc&-c^2\end{vmatrix}\\\\\\=-\dfrac {abc}{abc}\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\

=-1\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\\\\\=-1 \times -1 \begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\text{R.H.S}\\\\\text{Showed.}

3 0
2 years ago
Help with 7 and 8 and explain
Tems11 [23]

Answer:

7.  44^{\circ}

8.

Step-by-step explanation:

7. Using Cosine Rule

a^2=c^2 +c^2+bcCos(a)

=>a^2=20^2+15^2-2*20*15Cos(68^o)

   a^2=400.24

   a=20.00

=>Using Sine Rule

    20/Sin 68^o=15/sinB

      ABC=44^o

8

5 0
3 years ago
HELP PLEASE
Helga [31]
7.
Discounted price X
————————— = ———
Original Price 100

45 x
—- = —-
72 100

Cross multiply

45 times 100= 4500
72 times x= 72x

72x=4500

Divide

4500/72= 62.5%
4 0
3 years ago
The librarian was checking the thicknesses of several books and found that the average thickness of a book was 1.8 centimeters.
kvasek [131]

Answer:

1.2 cm

Step-by-step explanation:

1.8 * 5 = 9

9 - (1.4 + 1.9 + 2.1 + 2.4) = 1.2

1.2 + 1.4 + 1.9 + 2.1 + 2.4 = 9

9/5 = 1.8

4 0
3 years ago
A scuba diver started at 22 ft above sea level, then descended 40 ft. What integer best represents his new attitude?
jonny [76]

I think it is 62? Idk I added the 40 and 22.

6 0
4 years ago
Read 2 more answers
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