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2 years ago

3(r-1) -2(r+3) =0 anybody know the answer to that ?

Mathematics

1 answer:

agasfer [191]2 years ago

6 0

Answer:

r = 9

Step-by-step explanation:

3(r - 1) - 2(r + 3) = 0

First, use the distributive property.

3r - 3 -2r - 6 = 0

Now, isolate the variable "r" to one side by adding the opposite of the whole numbers to each side so it cancels it out on the left ide and adds it to the right.

3r - 3 -2r - 6 = 0

+3 +6 +3 +6

3r - 2r = 9

Subtract the r's.

r = 9

Now that we know r = 9, we can plug in 9 into the original (but distributed) expression for every time it uses the variable "r" to check our work.

3r - 3 -2r - 6 = 0

3(9) - 3 - 2(9) - 6 = 0

27 - 3 - 18 - 6 = 0

24 - 24 = 0

0 = 0

So, r = 9 is true.

Hope this helps! If you have any additional questions, please don't hesitate to ask me or your teacher to be sure you master the subject. Stay safe, and please mark brainliest!

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2 years ago

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Marina CMI [18]

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Explanation

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3 years ago

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Kobotan [32]

Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.

Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
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3 years ago

3tanx3x=3 square rooted

torisob [31]

Answer:

$\tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\where~x~is~an~integer.$

Step-by-step explanation:

tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\

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2 years ago

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