Ab and bc length and midpoint

What is the mixed number of 7/4

Nady [450]

7/4 = (4 + 3)/4 = 4/4 + 3/4 = 1 + 3/4 = 1 3/4

$\boxed{\dfrac{7}{3}=1\dfrac{3}{4}}$

5 0

2 years ago

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8 and 11/100 into a mixed number and a decimal

tiny-mole [99]

Answer:

8 11/100, 8.11, Hope this helpe :)

Step-by-step explanation:

8 0

2 years ago

An elementary school teacher wants to know if the words in a book are too difficult for her students. She reads the first senten

raketka [301]

Answer:

d.every word in the first sentence of the first page of every chapter.

Step-by-step explanation

the sample space means the set of total possible outcomes or ALL possible outcomes.

so here, the situation is about the teacher reading a sentence.

the favorable outcome is the set which has all the words that the students would not know from all the words read by the teacher or simply from the sample space.

since the teacher reads the first sentence on the first page in every chapter , all the words in that sentence will be sample in this situation.

7 0

2 years ago

Tell whether the ordered pair is a solution to the system.

DerKrebs [107]

Answer:

no

Step-by-step explanation:

no. substitute -1 for x and -2 for y.

the first one is -1 - 10

this equals -11 not 3

7 0

2 years ago

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Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago