Question

The cost of 2 bottles of water and 3 bags of pretzels is $7.05. The cost of a bag of pretzels is $1.35. Write a system of

Answer 1

Answer: the cost of one bottle of water is $1.5 and the cost of one bag of pretzels is $1.35.

Step-by-step explanation: Let's call "b" the cost of a bottle of water and "p" the cost of a bag of pretzels, in the first equation of the system, we need to express the total prize of 2 bottles of water and 3 bags of pretzels, so it would be:

2b+3p=$7.05

The second equation will express the cost of a bag of pretzels:

p=$1.35

Now, to solve the system we replace the second equation into the first one:

2b+3($1.35)=$7.05

2b=$7.05-$4.05

2b=$3

b=$1.5

So the cost of one bottle of water is $1.5 and the cost of one bag of pretzels is $1.35.

Answer 2

Step-by-step explanation:

let w be the cost of a bottle of water and p be the cost of a bag of pretzels

"2 bottles of water and 3 bags of pretzels is $7.05" can be written as

2w + 3p = 7.05    ------------- eq.1

"The cost of a bag of pretzels is $1.35" can be written as

p = 1.35 ------------- eq 2

Together, eq 1 and eq 2 make up your system of equations

To solve, take eq 2 and substitute this value int eq 1

2w + 3 (1.35) = 7.05

2w + 4.05 = 7.05

2w = 7.05 - 4.05

2w = 3

w = 1.5

Hence the cost of a bottle of water is $1.50