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3 years ago

The mass of a gold atom is 3.29 x 10-22 grams. The mass of a helium-4 atom is

Mathematics

1 answer:

blondinia [14]3 years ago

7 0

Answer:

um, I checked the questions you asked and we have the same questions, I think we might be in the same school lol

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The area of a triangle is 80x^5y^3. The height of the triangle is x^4y. What is the length of the base of the triangle?

svetoff [14.1K]

Area of a triangle is given by 1/2bh where b is the base and h is the perpendicular height of the triangle.
The area is 80x∧5y³ and the height is x∧4y
Thus; 80x∧5y³ = 1/2(x∧4y) b
160x∧5y³ = (x∧4y)b
b = (160x∧5y³)/ x∧4y)
b = 160xy²
Therefore, the base of the triangle is 160xy²

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3 years ago

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0.4 is 10 times as much as ?

dimulka [17.4K]

0.4 is 10 times as much as ? for answering this, we put x an unknown number such that 0.4 is 10 times as much as x, so it does mean 0.4 =10x, so for finding the value of x, we divids 0.4 by 10, x= 0.4/10=0.04. the answer is 0.4 is 10 times as much as 0.04Hope this helps. Let me know if you need additional help!

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3 years ago

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Help me and fast please

iogann1982 [59]

Answer: the answer is C

Step-by-step explanation: we know this because a straight line is 180 degrees. So given 140 degrees we know that g= 40.

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3 years ago

A person who weighs 100 pounds on earth weighs 16.6 lb on the moon. What is the independent variable? Explain why

Leviafan [203]

Independent variable (IV): something the scientist can change.

Thus, in this case, the IV can be the weight of the person.

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3 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$

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3 years ago

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