Answer:
The measure of the third arc is ![150\°](https://tex.z-dn.net/?f=150%5C%C2%B0)
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
![42\°=\frac{1}{2}(x-y)](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%28x-y%29)
----> equation A
![\frac{x}{y}=\frac{7}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%3D%5Cfrac%7B7%7D%7B3%7D)
-----> equation B
Substitute equation B in equation A and solve for y
![y=3*84\°/4=63\°](https://tex.z-dn.net/?f=y%3D3%2A84%5C%C2%B0%2F4%3D63%5C%C2%B0)
Find the value of x
![x=\frac{7}{3}(63\°)=147\°](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B7%7D%7B3%7D%2863%5C%C2%B0%29%3D147%5C%C2%B0)
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z
![147\°+63\°+z=360\°](https://tex.z-dn.net/?f=147%5C%C2%B0%2B63%5C%C2%B0%2Bz%3D360%5C%C2%B0)
![z=360\°-(147\°+63\°)=150\°](https://tex.z-dn.net/?f=z%3D360%5C%C2%B0-%28147%5C%C2%B0%2B63%5C%C2%B0%29%3D150%5C%C2%B0)
10% is the correct answer to this question
Volume of a sphere and a cone
We have that the equation of the volume of a sphere is given by:
![V=\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
We have that the radius of a sphere is half the diameter of it:
Then, the radius of this sphere is
r = 6cm/2 = 3cm
<h2>Finding the volume of a sphere</h2>
We replace r by 3 in the equation:
![\begin{gathered} V=\frac{4}{3}\pi r^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot3^3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%5Ccdot3%5E3%20%5Cend%7Bgathered%7D)
Since 3³ = 3 · 3 · 3 = 27
![\begin{gathered} V=\frac{4}{3}\pi3^3 \\ \downarrow \\ V=\frac{4}{3}\pi\cdot27 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi3%5E3%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%5Ccdot27%20%5Cend%7Bgathered%7D)
If we use π = 3.14:
![\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=\frac{4}{3}\cdot3.14\cdot27 \\ \downarrow \\ V=4.18\bar{6}\cdot27 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%5Ccdot27%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Ccdot3.14%5Ccdot27%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D4.18%5Cbar%7B6%7D%5Ccdot27%20%5Cend%7Bgathered%7D)
Rounding the first factor to the nearest hundredth (two digits after the decimal), we have:
4.18666... ≅ 4.19
Then, we have that:
![\begin{gathered} V=\frac{4}{3}\pi\cdot27 \\ \downarrow \\ V=4.19\cdot27 \\ =113.13 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%5Ccdot27%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D4.19%5Ccdot27%20%5C%5C%20%3D113.13%20%5Cend%7Bgathered%7D)
Then, we have that:
<h2>Finding the volume of a cone</h2>
We have that the volume of a cone is given by:
![V=\frac{1}{3}\pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2h)
where r is the radius of its base and h is the height:
Then, in this case
r = 3
h = 6
and
π = 3.14
Replacing in the equation for the volume:
![\begin{gathered} V=\frac{1}{3}\pi r^2h \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2h%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot3.14%5Ccdot3%5E2%5Ccdot6%20%5Cend%7Bgathered%7D)
Then, we have:
3² = 9
![\begin{gathered} V=\frac{1}{3}\cdot3.14\cdot3^2\cdot6 \\ \downarrow \\ V=\frac{1}{3}\cdot3.14\cdot9\cdot6 \\ V=\frac{1}{3}\cdot3.14\cdot54 \\ V=56.52 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot3.14%5Ccdot3%5E2%5Ccdot6%20%5C%5C%20%5Cdownarrow%20%5C%5C%20V%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot3.14%5Ccdot9%5Ccdot6%20%5C%5C%20V%3D%5Cfrac%7B1%7D%7B3%7D%5Ccdot3.14%5Ccdot54%20%5C%5C%20V%3D56.52%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Answer: the volume of the cone that has the same circular base and height is 56.52 cm³
If you would like to know how many centimeters are 27 millimeters, you can calculate this using the following steps:
1 cm ... 10 mm
x cm = ? ... 27 mm
1 * 27 = 10 * x
27 = 10 * x /10
x = 27/10
x = 2.7 cm
The correct result would be 2.7 cm.
Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%