Y=f(x)=(4)^x find f(x) when x=-2

Elimination pls help:))

pantera1 [17]

Answer:

(-2, -5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

3x + 2y = -16

-3x - 8y = 46

Step 2: Solve for y

Elimination

Combine 2 equations: -6y = 30
Divide -6 on both sides: y = -5

Step 3: Solve for x

Define equation: 3x + 2y = -16
Substitute in y: 3x + 2(-5) = -16
Multiply: 3x - 10 = -16
Add 10 on both sides: 3x = -6
Divide 3 on both sides: x = -2

6 0

3 years ago

I William page $54 for three cases of gum if each case of case has 24 packs what is the cost per pack of gum

Zina [86]

I'm not quite sure what you're asking, but I'll try to help anyway!

So if I'm not misinterpreting the question, you're asking how much one pack of gum would cost, and the packs are in a case which is in the deal of the 3 for $54

Then lets get started!

If you pay $54 for 3 cases, then how much would 1 case of gum be?

$54 / 3 = $18 per case

Then we consider the packs in a case.

Each one has 24 packs and you want to find how much 1 pack would cost. So do the same thing as before!

Cost of one case / number of packs
= $18 / 24
=$3/4 = 75 cents.

Hope this helps!

3 0

3 years ago

Hi can someone please help i don't know what the answer is. Parker ran 400 meters, 1 kilometer, and 3,000 centimeters. How many

Alenkasestr [34]

Answer:

1430 m

Step-by-step explanation:

1 km = 1000 m

3000 cm = 30 m

1000 + 400 + 30 = 1430

8 0

3 years ago

Find the missing coefficients y=ax^2-10x+c vertex :(-5,20)

Citrus2011 [14]

Remember, for $y=ax^2+bx+c$ the x value of the vertex is $\frac{-b}{2a}$

so
given
x value of vertex is -5
and
$y=ax^2-10x+c$
$\frac{-b}{2a}=\frac{-(-10)}{2a}=\frac{10}{2a}=$
$\frac{5}{a}=-5$
multiply both sides by a
5=-5a
divvide both sides by -5
-1=a
a=-1

$y=-1x^2-10x+c$
comlete the square
remember if we do
$y=a(x-h)^2+k$ (h,k) is the vertex
I know, we can subsitute the known values of te vertex
-5 for h and 20 for k then expand

$y=-1(x-(-5))^2+20$
$y=-1(x+5)^2+20$
$y=-1(x^2+10x+25)+20$
$y=-1x^2-10x-25+20$
$y=-1x^2-10x-5$

a=-1
c=-5

5 0

3 years ago

What is the following simplified product? assume b≥0 √b x √b

Brrunno [24]

$\sqrt{b} \times \sqrt{b} = { \sqrt{b} }^{2} = b$

5 0

4 years ago

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