May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
It has more time and the other takes less time
Step-by-step explanation:
if you subtract them it should be 4.66 seconds of difference hope this helps :)
Since the minimum is 72 the every grade must be equal or bigger than it
also 95 is the maximum therefore every grade must be equal or less than it

where is any quiz grade of any student in the class
Answer:
Whats the X given for this problem? ex.... X = 6 and the problem is:
2x (>) or (<) or = to 13
substitute ( x = 6 ) in 2x and you get 12 is < 13.