We have to calculate the probability of picking a 4 and then a 5 without replacement.
We can express this as the product of the probabilities of two events:
• The probability of picking a 4
,
• The probability of picking a 5, given that a 4 has been retired from the deck.
We have one card in the deck out of fouor cards that is a "4".
Then, the probability of picking a "4" will be:

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

We then calculate the probabilities of this two events happening in sequence as:

Answer: 1/12
If you want to solve the equation -5 - (15 * y - 1) = 2 * (7 * y - 16) - y, you can calculate this using the following steps:
-5 - (15 * y - 1) = 2 * (7 * y - 16) - y
-5 - 15 * y + 1 = 14 * y - 32 - y
-5 + 1 + 32 = 14 * y - y + 15 * y
28 = 28 * y /28
y = 1
The result is 1.
Answer:
f(x) = (x -3)^2 - 1
Step-by-step explanation:
f(x) = x^2 - 6x + 8
a = 1, b = -6 and c = 8
So we are finding half of the b equation (ignore the negative sign)
Half of 6 is 3, so we are going to square 3 (3^2 = 9) and add 9 to the left side and subtract 9 to the right side
(x) = (x^2 - 6x + 9) + (8 - 9)
You can tell the polynomial is a perfect square, so we will have to factor it using the perfect square method
(x^2 - 6x + 9)
square toot of x^2 is x and square root of 9 is 3 and the operation sign after the a number is a minus sign
(x -3)^2
Don't forget the rest of the equation from before
(x -3)^2 + (8 - 9)
(x -3)^2 - 1
So the equation is f(x) = (x -3)^2 - 1