Camel back Mountain = 15,168 inches (1,264 feet)
- 1 Penny = 0.061 (.0610) Inches
- 10 Penny = 0.61 (.610) Inches
- 100 Penny = 6.1 (6.10) Inches
- 1,000 Penny = 61 (61.0) Inches
- 10,000 Penny = 610 (610.0) Inches
<u>-SOLVING-</u>
10,000 Penny = 610 inches PLUS
1,000 Penny = 61 inches AND 61 inches x 5 = 305 (5,000 Penny)
100 Penny = 6.1 inches PLUS
10 Penny = 0.61 inches AND 0.61 inches x 6 = 3.66 (60 Penny)
1 Penny = 0.061 inches AND 0.061 inches x 8 = 0.488 (8 Penny)
-<u>FINAL ANSWER-</u>
610 + 305 + 6.1 + 3.66 + 0.488 = 925.248 Penny it would take.
<h2>
Answer: g(f(2)) = 11</h2>
Step-by-step explanation:
g(f(2)) is substituting the value of f(2) for x in g(x). But we must first find f(2).
We know that f (x) = ax² - 12
Since f(3) = 24
⇒ a(3²) - 12 = 24
9 a = 36
a = 4
∴ f(2) = (4)(2²) - 12
= 4
⇒ g(f(2)) = 2(4) + 3
= 11
Answer:
7
Step-by-step explanation:
1. Lets Combine Like Terms. The only combineable terms are 8 and 8. So if we combine them they will equal 16. And we will have (2n+2)=16
2. Let's isolate the variable. We can do this by subtracting 2 from both sides. This will come out to 2n+14.
3. Let's further isolate the variable. We can do this by dividing both sides by two, which will finally come out to n=7
Answer:
El espesor de un chip es de 0.12mm
Y el diámetro de un átomo de cobre, mide aprox:
0.00000000133 m
Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm
Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm
Primero, escribamos ambos valores en las mismas unidades, sabiendo que:
1m = 1000mm
Podemos reescribir:
0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm
Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm
Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:
N = (0.12mm)/(0.00000133mm) = 90,225.6
Redondeamos al próximo número entero:
N = 90,226
Esa es la cantidad de átomos que se necesitan.
(x+2)^2 over x+2
x^2+4 \x+2
x+2
