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mash [69]
3 years ago
14

complete and balance the molecular equation including phases for aqueous Solutions of ammonium carbonate and lead (II) nitrate?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
8 0
The balanced equation is

(NH4)2CO3 + Pb(NO3)2 = PbCO3 + 2(NH4NO3)

Where PbCO3 is in solid form and NH4NO3 is aqueous as a precipitate of lead carbonate
You might be interested in
Describe the three types of convergent plate boundaries?
icang [17]

Hi friend! Hope you find this response helpful! :)

When two tectonic plates move toward each other and collide, they form a convergent plate boundary. There are three types of convergent plate boundaries: oceanic-oceanic boundaries, oceanic-continental boundaries, and continental-continental boundaries. Each one is unique because of the density of the plates involved.

7 0
3 years ago
Need to find moles and molarity
valentinak56 [21]
You multiply the molarity by the volume in litres.
Explanation:
Molarity is the number of moles of a substance in one litre of solution. The official symbol for molarity is “c” (concentration), but many people use the old symbol “M”.
M
=
n
V
, where
n
is the number of moles and
V
is the volume in litres.
We can rearrange this equation to get the number of moles:
n
=
M
×
V

Example
:
How many moles of
NaCl
are contained in 0.300 L of 0.400 mol/L
NaCl
solution?
Solution:
n
=
0.300
L soln
×
0.400 mol NaCl
1
L soln
=
0.120 mol NaCl
4 0
3 years ago
you are given mixtures containin gthe following compounds. Which compound in each pair could be separated by stirring the solid
ExtremeBDS [4]

Answer:

(A) NaOH and Ca(OH)2: Ca(OH)2

(B) MgCl2 and MgF2: MgF2

(C) Agl and KI: AgI

(D) NH4Cl and PbCl2: PbCl2

Explanation:

We need to see the solubility in water, at similar temperatures, for each compound and see which one is less soluble than the other:

NaOH: 1000 g/L (25 °C)

Ca(OH)2: 1.73 g/L (20 °C)

MgCl2: 54.3 g/100 mL (20 °C)

MgF2: 0.013 g/100 mL (20 °C)

Agl: 3×10−7g/100mL (20 °C)

KI: 140 g/100mL (20 °C)

NH4Cl: 383.0 g/L (25 °C)

PbCl2: 10.8 g/L (20 °C)

After the comparison made we can conclude that the less soluble, after saturation of water, will precipitate first.

3 0
4 years ago
What pattern do you observe in the coefficients of the hydrocarbon (CxHy) and water (H2O)? How do you explain this pattern?
balu736 [363]

The coefficients of the hydrocarbon and water is 61 and it is explained below.

Explanation:

We have to  balance the chemical equation that describes the combustion of octane C₈H₁₈. The combustion of octane involves burning this hydrocarbon in the presence of excess oxygen,O 2.  Because octane is a hydrocarbon, that is the compound that contains only carbon and hydrogen, the reaction will produce two products carbon dioxide CO 2 and water H 2 O.

The unbalanced chemical equation is

C₈H₁₈ + O₂ → CO₂ + H₂O

To balance this equation, we have 8 present on the reactant side, so multiply the carbon dioxide by  8  to get  8  atoms of carbon on the products side.

C₈H₁₈ + O₂ → 8 CO₂ + H₂O

Now, we have 18  on the reactant side and  2  on the products side, so multiply the water molecule by  9  to get

C₈H₁₈ + O₂ → 8 CO₂ + 9 H₂O

8 * 2 atoms O + 9 *1 atoms O = 25 atoms O

By adding fractional coefficient to O₂ we get

C₈H₁₈ + \frac{25}{2}O₂ → 8 CO₂ + 9 H₂O

Multiply all the coefficients by 2 we get,

2C₈H₁₈ + (\frac{25}{2} * 2) O₂ → 8 * 2 CO₂ + 9* 2 H₂O

The balance equation is

2C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

Add the coefficients to get their sum

= 2 +25 + 16 +18 = 61

Thus, The coefficients of the hydrocarbon and water is 61

6 0
3 years ago
СН3 – СН = СН2 + НCl → help help help help​
Alex

СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃

<h3>Further explanation</h3>

Alkenes are unsaturated hydrocarbons that have a -C = C- double bond.

If there are 2 double bonds it is called an alkadiene, and if there are three double bonds it is called an alkatriene

General formula for Alkenes: CnH2n

addition reactions to alkenes follow Markovnikov's rule. in the addition reaction of hydrogen halide (HX), the halogen atom (X) will be bonded to the carbon atom that binds less H atom.

If the double-bonded carbon atom has the same number of H atoms attached to it, then the X atom will tend to be attached to the carbon atom with the longer alkyl group.

Addition reaction of propene compounds with HCl

СН₃ – СН = СН₂ + НCl → CH₃-CHCl-CH₃

CH - this carbon atom binds fewer H atoms, so Cl is bonded to this bond

5 0
3 years ago
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