I am going to say D and C.
The force exerted on the parked car by the moving car is –30000 N
To solve this question, we'll begin by calculating the deceleration of the moving car. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.5 s
<h3>Deceleration (a) =?</h3>

<h3>a = - 20 m/s</h3>
Finally, we shall determine the force exerted by the moving car on the parked car. This can be obtained as follow:
Mass of moving car (m) = 1500 Kg
Acceleration (a) = - 20 m/s
<h3>Force (F) =.?</h3>
F = ma
F = 1500 × (-20)
<h3>F = -30000 N</h3>
NOTE: The negative sign indicate force is in opposite direction to the parked car.
Therefore, the force exerted on the parked car by the moving car is –30000 N
Learn more: brainly.com/question/15430805
<span>Calcium oxide is the element that has a basic oxide of the type MO which is used to treat acidic soils.
Hope that helps. -UF aka Nadoa
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Answer : Neutrons.
Explanation : Usually in nuclear fission reactions the atoms with a heavy nucleus is bombarded with neutrons. Which breaks the parent atom into many smaller atoms resulting in fission products.