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Anni [7]
3 years ago
11

What is the correct formula for potassium sulfite? khso khso4 k2so4 k2so3

Chemistry
2 answers:
Aleonysh [2.5K]3 years ago
7 0

<u>Answer:</u> The chemical formula for potassium sulfite is K_2SO_3

<u>Explanation:</u>

We are given a chemical compound having name potassium sulfite. This compound is formed by the combination of potassium ions and sulfite ions.

Potassium is the 19th element of periodic table having electronic configuration of [Ar]4s^1.

This element will loose 1 electron to form K^{+} ion

Sulfite ion is a polyatomic ion having chemical formula of SO_3^{2-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

Hence, the chemical formula for potassium sulfite is K_2SO_3

Verdich [7]3 years ago
3 0
Potassium sulfite<span> (K</span>₂<span>SO</span>₃<span>)

hope this helps!</span>
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In a sample of liquid water (H2O), which property differs among the water molecules?
garik1379 [7]

In a sample liquid water, a property that differs among the water molecules is its own orientation and space. The explanation of the answer to the question is because the number of the oxygen and hydrogen atoms and the hydrogen and atoms’ arrangement will never change and will always be the same for each of the water molecule. The strength of the bond of it also does not change and stays the same.

3 0
3 years ago
Seasonal variation on earth is due to the
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7 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
Help pleaseeeeeeeeeee
hichkok12 [17]

Answer:

D 1 and 3 only I am not sure

Explanation:

6 0
3 years ago
The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.
maw [93]
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

7 0
3 years ago
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