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natita [175]
3 years ago
5

Need help fixing my answer, help would be appreciated. I am supposed to complete and balance this equation for an acid-base reac

tion. The problem is: HC2H3O2(aq)+Ca(OH)2(aq)->
Chemistry
1 answer:
Gnoma [55]3 years ago
5 0
Ca(OH)2 is only partially soluble in water

If you wrote it as Ca(OH)2(s) you may get a different response

The equation is balanced correctly, its the net ionic eq

hope this helps
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Hybridization refers to the mixing of atomic orbitals in an atom. The number of hybrid orbitals needs to be equal to the number of orbitals that have involved in prior to mixing.  

The isolated atoms cannot prevail in a hybridized state as the atom in an isolated state do not form any kind of bond with the other atom, due to which the atomic orbitals do not go through the process of hybridization.  


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The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for t
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Answer:

B

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

\displaystyle 3\text{H$_2$} +  \text{N$_2$} \longrightarrow 2\text{NH$_3$}

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \\ \\ & =  0.102\text{ g H$_2$}\end{aligned}

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

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