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larisa [96]
3 years ago
14

I need help in my alg assignment, I'm trying to finish up my class and my friend explain this to me but I don't understand and c

an't

Mathematics
1 answer:
Alex3 years ago
3 0
50 boys 35 girls 4.40 times 5 is 22+14=36
so all your doing here is 35 times 0.4 because their are 35 girls and you multiple that by 0.4
same thing for the guys anyway answer is 36
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Whats the answer please help
Mice21 [21]

Answer:

On what?

Step-by-step explanation:

6 0
3 years ago
A pair of shoes usually sells for $66. If the shoes are 40% off, and sales tax is 5%, what is the total price of the shoes, incl
irga5000 [103]
Discount;
66 * 0.4 = 26.40
66 - 26.4 = 39.60

Tax;
66 * 0.05 = 3.30

Total Price:
39.60 + 3.30 = 42.90

$42.90
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3 years ago
Worksheet
Svetlanka [38]

Answer:

1a. 495 miles. 1b. 184.8 miles. 2a. 68 km. 2b. 32 kg

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
-8<2x-4<4 solve the inequality
il63 [147K]

Answer:

Step-by-step explanation:

The inequality will be split into two

It is know that, if a<b<c

Then a<b and b<c

-8<2x-4<4

Apply that to this

Then,

-8<2x-4. Equation 1

Also,

2x-4<4 equation 2

Solving equation 1

-8<2x-4

Add 4 to both side of the equation

-8+4<2x-4+4

-4<2x

Divide both sides by 2

-4/2<2x/2

-2<x

Note, if a is less than b, then, b is greater than a, e.g. 4 is less than 10, this implies 10 is greater than 4

Therefore,

-2<x

Then, x greater than -2

Equation 2

2x-4<4

Add 4 to both side of the inequalities

2x-4+4<4+4

2x<8

Divide both side by 2

Then,

2x/2<8/2

x<4

Therefore x is between -2 and +4.

Check attachment for graphical solution

7 0
3 years ago
What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


5 0
4 years ago
Read 2 more answers
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