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bezimeni [28]
2 years ago
7

(08.04 MC) Find the sum of an 8-term geometric sequence when the first term is 7 and the last term is 114,688 and select the cor

rect answer below.
Mathematics
1 answer:
klemol [59]2 years ago
3 0
Starts off at 7 ends at114688, subtract them, 114681. Now there are 8 terms so subtract 1 because you're starting from the beginning, that leaves 7. Now divide 114681/7=16,383 difference per point, Now 1st pt is 7 2nd is 16390 3rd is 32773 4th is 49156 5th is 65539 6th is 81922 7th is 98305 8th is 114688 Now add these= 458780
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Answer:

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e) b = a^2 + 7

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Step-by-step explanation:

a) x - values are 4, 5, 6, 7

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b) d values are : 1, 2, 3, 4

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c) w values are : 0, 1, 2, 3

p value are : 7, 17, 27, 37

p = 10w + 7

d) x values are : 0, 1, 2, 3

y values are: -5, -2, 1, 4

y = 3x - 5

e) a values are : -4, -3, -2, -1

b value are : 23, 16, 11, 8

b = a^2 + 7

f) n values are : 0, 1, 2, 3

p values are : 50, 42, 34, 26

p = 50 - 8n

Thank you.

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