Answer:
10
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3x−5=
1
2
x+2x
3x+−5=
1
2
x+2x
3x−5=(
1
2
x+2x)(Combine Like Terms)
3x−5=
5
2
x
3x−5=
5
2
x
Step 2: Subtract 5/2x from both sides.
3x−5−
5
2
x=
5
2
x−
5
2
x
1
2
x−5=0
Step 3: Add 5 to both sides.
1
2
x−5+5=0+5
1
2
x=5
Step 4: Multiply both sides by 2.
2*(
1
2
x)=(2)*(5)
x=10
The equation of parabola is 
. If a is positive and 
is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.
Tha canonical equation of parabola is 
, where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.
Answer: correct choice is A.
Answer:
80
Step-by-step explanation:
The Two-Tangent Theorem states that if two tangent segments are drawn to one circle from the same external point, then they are congruent
13+13+9+9+12+12+6+6= 80
Answer:
B is the answer foks thanks for looking
Step-by-step explanation:
They looked around and then rushed toward each other. A cry of alarm surged through Tompkins Square Park. Was this a fight to the death instead of a boxing match?
The fear soon gave way to wave upon wave of cheering as the two amigos embraced.
No matter what the decision, they knew they would always be champions to each other.
(continued)
Based on the passage, how do the boys resolve their conflict?
They decide to fight to the death.
They decide not to care who the winner is.
They decide to fight a rematch.
They decide to end their friendship.
Trinomial 2x² + 4x + 4.
It's of the form ax²+bx+c and it's discriminant is Δ=b² - 4.a.c
(in our case Δ = 4² - (4)(2)(4) → Δ = - 32
We know that: x' = -1 + i and x" = -1 - i
If Δ > 0 we have 2 rational solutions x' and x"
If Δ = 0 we have1 rational solution x' = x"
If Δ < 0 we have 2 complex solutions x' and x", that are conjugate
In our example we have Δ = - 16 then <0 so we have 2 complex solutions
That are x'= [-b+√Δ]/2.a and x" = [-b-√Δ]/2.a
x' =
