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baherus [9]
3 years ago
9

Three points lie on the same straight line. If each point can act as an endpoint, how many distinct line segments can be formed

using the set of points?one
three
four
five
two
Mathematics
2 answers:
NeX [460]3 years ago
6 0
The line would have two segments
Deffense [45]3 years ago
5 0
Two because it would have two rays at the end which aren't line segments. The line would look like <---*----*-----*---> So it only would have two segments
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Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

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Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

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(h,k)

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(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

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\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

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Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
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