1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yulyashka [42]
2 years ago
7

Vector V is shown in the graph below.

Mathematics
2 answers:
Lady_Fox [76]2 years ago
8 0

Answer:

v = -8i - 6j

Step-by-step explanation:

The starting point is (9, 9)

The direction of the vector is the direction of the arrowhead.

The i is the horizontal component.

The j is the vertical component.

Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).

Therefore, v = -8i - 6j

UkoKoshka [18]2 years ago
7 0

Answer:

  (b)  v = -8i -6j

Step-by-step explanation:

The unit vectors in the x- and y-directions are i and j, respectively.

The vector v shown in the graph extends from x=9 to x=1, or (1 -9) = -8 units in the x-direction.

It extends from y=9 to y=3, or (3-9) = -6 units in the y-direction.

Represented as a sum of x- and y-vectors, that is ...

  v = -8<em>i</em> -6<em>j</em>

You might be interested in
Cos A+cosB+CosC=1+4sinA/2*sinB/2*sinC/2
Scrat [10]
Socratic use det app
5 0
3 years ago
What is a cubic polynomial function in standard form with zeros 1,1,and -3?
Mekhanik [1.2K]

Answer:

f(x) = x³ + x² - 5x + 3

Step-by-step explanation:

The cubic polynomial has zeros at 1, 1, - 3.

Therefore, x = 1, 1, - 3 are the roots of the polynomial and hence, (x - 1), (x - 1) and (x + 3) will be factors of the cubic polynomial.

Hence, we can write the polynomial as a function of x as

f(x) = (x - 1)(x - 1)(x + 3)

⇒ f(x) = (x² - 2x + 1)(x + 3)

⇒ f(x) = x³ - 2x² + 3x² + x - 6x + 3

⇒ f(x) = x³ + x² - 5x + 3

So, this is the cubic polynomial function in standard form. (Answer)

8 0
3 years ago
(5+2 i)(4-3i) - (5-2yi)(4-3i) in a + bi form, where y is a real number.
ElenaW [278]
<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)

Factorize out (4 -3i)

(4 -3i)( (5 +2i) - (5 -2yi) )

=  </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>

=  </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>

= (4 -3i)(2i + 2yi)

= (4 - 3i)(2 + 2y)i.    Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)           
                      =  8 - 6i + 8y - 6yi
                      =  8 + 8y - 6i - 6yi

(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i                Note: i² = -1
                       =  8i  + 8yi - 6i² - 6yi²
                       =  8i  +  8yi - 6(-1) - 6y(-1)  
                       =  8i  +  8yi  + 6 + 6y
                       =  6 + 6y + 8i + 8yi
                       =  (6 + 6y) + (8 + 8y)i    In the form a + bi
5 0
2 years ago
All about easy points here
RoseWind [281]

Answer:

90

Step-by-step explanation:

The formula for right triangular prisms is simple; 1/2 × a × b × c. So simply plug in your numbers (doesn't matter the order you plug in).

1/2 × 12 × 5 × 3 = 90

5 0
3 years ago
Read 2 more answers
Help me plz this due tommorow and i need help with this
olga2289 [7]
1) last number times 4 and subtract 1
2) last number times2 and add 2
3) you figure out
4 0
2 years ago
Other questions:
  • The answer is a=6 , b=-5. Can someone explain how to get thosse two anwers?​
    6·1 answer
  • A small town surveys 250 adults, 180 of which are parents, about whether or not a park should be expanded. The results showed th
    9·1 answer
  • What is the missing operation? 48?(-8)=(-6)​
    6·1 answer
  • Study the table below. Label the table as proportional or non-proportional. Explain your reasoning.
    5·1 answer
  • Helpppppppppppppppppppppppppp
    15·1 answer
  • Fundamental Counting Principle (L1)
    15·1 answer
  • Can anyone help me with this ?
    12·1 answer
  • No solution:<br> 3(x-4/3)=3x+?
    10·1 answer
  • 8^x=2 what is x please help
    7·2 answers
  • X
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!