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3 years ago

10

I need help with this math problem ?! ASAP

1 answer:

alisha [4.7K]3 years ago

5 0

I believe the answer is C because i have did that question before and got it right but if not let me kniw

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X (dy/dx) = (y-1/y+1)-y

notsponge [240]

F' $( \frac{y-1}{y+1})-y$ =
f' $( \frac{y-1}{y+1})$ -f'(y) [/tex]=
$\frac{f'(y-1)(y+1)-f'(y+1)(y-1)}{(y+1)^2} -1$ =
$\frac{(f'(y)-f'(1))(y+1)-(f'(y)+f'(1))(y-1)}{(y+1)^2} -1$ =
$\frac{(1-0)(y+1)-(1-0)(y-1)}{(y+1)^2} -1$ =
$\frac{(1)(y+1)-(1)(y-1)}{(y+1)^2} -1$ =
$\frac{(y+1)-(y-1)}{(y+1)^2} -1$ =
$\frac{y+1-y+1}{(y+1)^2} -1$ =
$\frac{2}{(y+1)^2} -1$

8 0

3 years ago

A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x

Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

$y=\sqrt{x}$

Point P lie on this curve so any general point on curve can be written as $(x,\sqrt{x})$

and $\frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s$

Distance between Point P and (2,0)

$P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}$

P at x=3 P=2

rate at which distance is changing is

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s$

8 0

3 years ago

Write the expression:<br><br> The quotient of the sum 3y and 5, and y squared.

lesya692 [45]

Answer:

(3y + 5) / (y^2)

Step-by-step explanation:

Sorry it's not actually in fraction format. That little button thing is having troubles atm on my end. Hope this is okay

6 0

3 years ago

LeBron James made 16 baskets. Some were 2-pointers, and some were 3-pointers. He scored a total of 39 points.How many 2-pointers

nignag [31]

Answer: 2pointers (9 baskets) 3pointers(7 baskets)

Step-by-step explanation:

(2*9)=18 (3*7)=21

21+18=39

5 0

3 years ago

Pleaseeeee neeeddd helppp asappp

Rufina [12.5K]

ANSWER:

Segment TS is a Chord

If AR = 14 , then QS = 14 ×2 = 28

∆ATS is an Isosceles Triangle

<em><u>HOPE</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> HELP</u></em><em><u> </u></em><em><u>YOU </u></em><em><u>,</u></em><em><u> FOR</u></em><em><u> ANY</u></em><em><u> QUESTION</u></em><em><u> PLEASE</u></em><em><u> ASK</u></em><em><u> </u></em><em><u>ME</u></em>

7 0

2 years ago