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PilotLPTM [1.2K]
3 years ago
15

Find the 32nd term in the sequence whose general term is an = -3 + 4 (n-1) Work?

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
5 0

Answer:

121

Step-by-step explanation:

T32 = -3 + 4 (n - 1)

Let n = 32

T32= -3 + 4 (32 - 1)

= -3 +4(31)

= -3 + 124

= 121

Sav [38]3 years ago
4 0

Answer:

121

Step-by-step explanation:

To find the 32 nd term substitute n = 32 into the general term formula

a_{32} = - 3 + (4 × 31) = - 3 + 124 = 121

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3 years ago
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3 years ago
The league championship 800 meter race has 6 runners.
s2008m [1.1K]

Answer: 120

Step-by-step explanation:

Given : The league championship 800 meter race has 6 runners.

The number of positions = 3

Since order matters here , so we use Permutation.

The permutation of n things taking r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of different ways they place first, second, and third :_

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In order to find which <u>expression</u> is <u>equivalent</u> to \sqrt[4]{x^{10}}, <u>simplify</u> all given expressions:

0.

\sqrt[4]{x^{10}}=x^{\frac{10}{4}}=x^{\frac{5}{2}}=x^{2.5}.

1.

x^2(\sqrt[4]{x^2})=x^2\cdot x^{\frac{2}{4}}=x^2\cdot x^{\frac{1}{2}}=x^2\cdot x^{0.5}=x^{2.5}.

2.

x^{2.2}.

3.

x^3(\sqrt[4]{x} )=x^3\cdot x^{\frac{1}{4}}=x^3\cdot x^{0.25}=x^{3.25}.

4.

x^5.

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7 0
3 years ago
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