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yaroslaw [1]
3 years ago
12

Solve for k, m = 3kx/7 - 9

Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

(7m + 63)/3x = k

Step-by-step explanation:

<em>m=3kx/7 - 9</em>

<u><em>add 9 to both sides:</em></u>

m+ 9 = 3kx/7

<u><em>multiply both sides by 7:</em></u>

7(m+9) = 3kx

<u><em>distribute the 7:</em></u>

7m+63 = 3kx

<u><em>divide both sides by 3x:</em></u>

<u>(7m + 63)/3x = k</u>

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A. $459

Step-by-step explanation:

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A typical lap around a track in the United States has length of 440 yards. How many lap would need to be complete to run a mile?
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3 0
3 years ago
identify and equation in point-slope form for the line perpendicular to y=-1/2x-7 that passes through (-3,-2)
bazaltina [42]

Answer:

  y +2 = 2(x +3)

Step-by-step explanation:

The equation in point-slope form for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

The slope of your given line is the coefficient of x, -1/2. The slope of a perpendicular line will be the negative reciprocal of that: -1/(-1/2) = 2. So, you have m = 2, (h, k) = (-3, -2), and your desired equation is ...

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8 0
3 years ago
A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a
Natali [406]

Answer:

(a)

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(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

p^4 (1-p)

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

                                    p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

7 0
3 years ago
If 7 || m, find the value of x<br> (9x - 4)' Us 4+ (5x + 16)"
KonstantinChe [14]

Answer:

Step-by-step explanation:

9x - 4 + 5x + 16 = 180

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14x = 168

x = 12

7 0
3 years ago
Read 2 more answers
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