All categories

3 years ago

If 8=2, 7=31 and ead=102,find 9

Mathematics

1 answer:

g100num [7]3 years ago

3 0

M<7 + m<8 + m<9 = m<EAD

31 + 22 + m<9 = 102

53 + m<9 = 102

m<9 = 49

You might be interested in

Explain why f(x) is continuous at x=3

Elina [12.6K]

Answer:

f is not defined at x = 3 ⇒ answer (b)

Step-by-step explanation:

∵ f(x) = x² - x - 6/x² - 9 is a rational function

∴ It will be undefined at the values of x of the denominator

∵ The denominator is x² - 9

∵ x² - 9 = 0 ⇒ x² = 9 ⇒ x = ±√9

∴ x = ± 3

∴ f(x) can not be defined at x = 3

∴ The f(x) can not be continuous at x = 3

∴ The answer is (b)

6 0

3 years ago

Read 2 more answers

10. 2x + 7y = 1 2x - 4y = 12 Solve for y

adoni [48]

Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

$2x\ +\ 7y\ =\ 1$ ....(1)

$2x\ -\ 4y\ =\ 12$ ....(2)

So, to solve for y, first we solve for x in equation (2):

$2x-4y=12$

⇒ $2x=12+4y$

Dividing both sides by 2,

⇒ $x=6+2y$

Now, substituting the value of x in equation (1):

$2x+7y=1$

⇒ $2(6+2y)+7y=1$

⇒ $12+4y+7y=1$

⇒ $12+11y=1$

⇒ $11y=1-12$

⇒ $11y=-11$

Dividing both sides by 11,

⇒ $y=-1$

Therefore, the solution for y = -1.

7 0

2 years ago

Find the length of the third side. If necessary, write in simplest radical form.

Mazyrski [523]

Answer:

$\boxed {\boxed {\sf 8}}$

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

$a^2+b^2=c^2$

Where a and b are the legs of the triangle and c is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

$a= 7 \\b= \sqrt{15}$

Substitute these values into the formula.

$(7)^2+(\sqrt{15})^2=c^2$

Solve the exponents.

(7)²= 7*7=49

$49+ (\sqrt{15})^2=c^2$

(√15)²=√15*√15=15

$49+15=c^2$

Add.

$64=c^2$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c$