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3 years ago

Algebra 2 questions

Mathematics

1 answer:

Debora [2.8K]3 years ago

3 0

Answer is y/y+x for dis problem

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The box is a square. It's perimeter is 48 inches. The pizza has a circumference of 37.68 inches. What is the difference in the a

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23.6 i hope it helps I'm not sure if its right

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3 years ago

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AveGali [126]

With a saw?

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3 years ago

Find the length of AB. Leave

vovikov84 [41]

Answer:

AB = 3π

Step-by-step explanation:

See attachment for correct format of question.

Given

From the attachment, we have that

θ = 20°

Radius, r = 27

Required

Find length of AB

AB is an arc and it's length can be calculated using arc length formula.

$Length = \frac{\theta}{360} * 2\pi r$

Substitute 20 for θ and 27 for r

$Length = \frac{20}{360} * 2\pi *27$

$Length = \frac{20 * 2\pi * 27}{360}$

$Length = \frac{1080 \pi}{360}$

$Length = 3\pi$

Hence, the length of arc AB is terms of π is 3π

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3 years ago

Find the oth term of the geometric sequence 7, 14, 28, ...

yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

$a_n=a_1\cdot r^{n-1}$

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

$\frac{14}{7}=2,\:\quad \frac{28}{14}=2$

The ratio of all the adjacent terms is the same and equal to

$r=2$

now substituting r = 2 and a₁ = 7 in the nth term

$a_n=a_1\cdot r^{n-1}$

$a_n=7\cdot \:2^{n-1}$

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

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3 years ago

Solve the compound inequality. graph the solution

Juli2301 [7.4K]

-2 <= 2x - 4 < 4
-2 + 4 <= 2x < 4 + 4
2 <= 2x < 8
2/2 <= x < 8/2
1 <= x < 4

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3 years ago