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Marizza181 [45]
3 years ago
13

Algebra 2 questions

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0
Answer is y/y+x for dis problem
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for every three short horned lizards there are two fence lizards. If there are 54 short horned lizards how many fence lizards ar
Komok [63]

Answer: 36

Step-by-step explanation:

54/3 = 18 x 2 = 36

8 0
3 years ago
The frequency distribution representing the number of frequent flier miles accumulated by employees at Brumley Statistical Consu
alisha [4.7K]

Answer:

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

Step-by-step explanation:

The given frequency distribution representing the number of frequent flier miles accumulated by the employees in a company.                        

Frequent Flier Miles (000) Frequency

0                     up to 3 5

3                      up to 6 12

6                      up to 9 23

9                     up to 12 8

12                   up to 15 2

Total                       50

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

b. Convert the frequency distribution to a cumulative frequency distribution.

We make the cumulative frequency distribution from the frequency distribution by adding up a frequency and all other frequencies below it.                

Frequent Flier Miles Frequency Cumulative frequency

0 up to 3                                5 5

3 up to 6                                      12 17

6 up to 9                                      23 40

9 up to 12                               8 48

12 up to 15                               2 50

Total 50

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

8 0
3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
2 years ago
Whats is 67.24 as a mixed number
masha68 [24]
<span>67 24 out of 100 i believe</span>
6 0
3 years ago
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How many different arrangements of the letters in the word SCHOOL are there?
pogonyaev
36; there are 6 letters in the word school so if you multiple it by 6 which is the amount of different places one letter could be, the result would be 36
4 0
3 years ago
Read 2 more answers
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