Answer:
no solution
Step-by-step explanation:
6x - 3y = 7 → (1)
- 2x + y = - 8 → (2)
multiplying (2) by 3 and adding to (1) eliminates the variables
- 6x + 3y = - 24 → (3)
add (1) and (3) term by term
0 + 0 = - 17
0 = - 17 ← false statement
This indicates the system has no solution
Answer: It will be (2,-5) and (6,3) because they are one the slope line
Step-by-step explanation:
Hope is Helped
First, you need to get delta which is b squared minus 4ac. If delta is higher than cero, the polynomial has two solutions, if it is less, the polynomial has no real solutions and if it is the same, it has one solution.
Although that is only for second grade ecuations
Answer:
(x, y) = (40, 30)
Step-by-step explanation:
A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.
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An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:
y = 110 -2x . . . . . . subtract 2x from both sides
Using this in the first equation gives ...
3x -4(110 -2x) = 0 . . . . substitute for y
11x = 440 . . . . . . . . . simplify, add 440
x = 40 . . . . . . . . . . divide by 11
y = 110 -2(40) = 30
The solution is (x, y) = (40, 30).
Answer:
y = 3x + 7
Step-by-step explanation:
First, we will solve for the slope (m).
The formula for slope is: m = 
m =
--- enter the points into the formula
m =
--- simplify
m = 3 --- simplify
Now we will solve for the y-intercept (b).
y = mx + b
y = 3x + b --- substitute the slope into the equation
-20 = 3(-9) + b --- substitute the x and y of either point into the equation
-20 = -27 + b --- simplify
7 = b --- add 27 to both sides
b = 7
Done.
y = 3x + 7