The answer is c i have a 3 button mouse C.
Answer:
pH = 13.1
Explanation:
Hello there!
In this case, according to the given information, we can set up the following equation:

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

And the resulting concentration of KOH and OH ions as this is a strong base:
![[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M](https://tex.z-dn.net/?f=%5BKOH%5D%3D%5BOH%5E-%5D%3D%5Cfrac%7B0.00576mol%7D%7B0.012L%2B0.032L%7D%3D0.131M)
And the resulting pH is:

Regards!
Answer:
0.16 M
Explanation:
Data provided as per the question is below:-
Volume of
= 0.22 L
The Volume of NaOH = 0.18 L
Morality of NaOH = 0.2
According to the given situation, the calculation of the concentration of the
is shown below:-
For equivalence,
Number of the equivalent of
= Number of equivalents of NaOH


= 0.16363 M
or
= 0.16 M
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