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3 years ago

which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --> KOH + Cr2O3 +SO2

1 answer:

6 0

You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.

- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6

- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.

So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.

Answer: Cr has a change in oxidation number of - 3.

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Molarity is represented by the symbol m true or false?

Allisa [31]

The answer to your question is False, my good man! Hope this helps!

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3 years ago

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What is the number if moles of nitrogen gas which react with 18 g of magnesium to form magnesium nitride compound?(mg=24,N=14)

makvit [3.9K]

Answer:

It is true. a) 0.25 mol

Explanation:

Hello there?

To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.

The chemical equation is;

3Mg(s) + N2(g) => Mg3N2(s)

1 mole of Mg = 24g

We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)

From our equation,

Mole ratio = 3 : 1, (Mg : N2)

1 mol Mg = 24g

x mol Mg = 18g

x mol Mg = (18/24) = 0.75 mol Mg

But mole ratio = 3 : 1 (Mg : N2)

This means that 3 => 0.75 mol Mg

What about ratio 1 of N2?

N2 = (0.75 mol ÷ 3)/1

= 0.25 mol N2

I hope this helps you to understand better. Have a nice studies. 

6 0

3 years ago

The highest energy occupied molecular orbital in the C-C bond of the C2 molecule is?

Butoxors [25]

The highest energy occupied molecular orbital in the C-C bond of the C₂ molecule is 2pπ orbitals.

<h3>What is Molecular Orbital Theory?</h3>

According to this theory,

Molecular orbitals are formed by intermixing of atomic orbitals of two or more atoms having comparable energies
The number of molecular orbitals formed is equal to the number of atomic orbitals combined.
The shape of molecular orbitals formed depends on the type of atomic orbitals combined
Only atomic orbitals having comparable energies and the same orientation can intermix
Bonding M.O. is formed by the additive effect of atomic orbitals and thus, has lower energy and high stability.
Antibonding M.O. is formed by the subtractive effect of atomic orbitals and thus, has higher energy and low stability.
Bonding M.O. is represented by $\sigma, \pi, \delta$ while Antibonding M.O. is represented by $\sigma^*, \pi^*, \delta^*\\$

Molecular Orbital Diagram of C₂

Learn more about Molecular Orbital Theory:

brainly.com/question/17371976

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1 year ago

In a chemical reaction, 36 grams of hydrochloric acid reacts with 40 grams of sodium hydroxide to produce sodium chloride and wa

Elena L [17]

The answer is The mass of sodium chloride formed is less than 76 grams.

Remember Mass is never gained or loss in any chemical reactions

So,

hydrochloric acid + sodium hydroxide => sodium chloride + water
Total 76 gram Total will also 76 gram

In this case, the mass of sodium chloride will be less than 76 gram because we need to take out the mass of the water.

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3 years ago

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A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y , that is, X more readily reac

Margaret [11]

Answer:

(1) cathode: Y

(2) anode X

(3) electrons in the wire flow toward: Y

(4) electrons in the wire flow away from: X

(5) anions from the salt bridge flow toward X

(6) cations from the salt bridge flow toward Y

(7) gains mass: Y

(8) looses mass X

Explanation:

The voltaic cell uses two different metal electrodes, each in an electrolyte solution. The anode will undergo oxidation and the cathode will undergo reduction. The metal of the anode will oxidize, going from an oxidation state of 0 (in the solid form) to a positive oxidation state, and it will become an ion. At the cathode, the metal ion in the solution will accept one or more electrons from the cathode, and the ion’s oxidation state will reduce to 0. This forms a solid metal that deposits on the cathode. The two electrodes must be electrically connected to each other, allowing for a flow of electrons that leave the metal of the anode and flow through this connection to the ions at the surface of the cathode. This flow of electrons is an electrical current that can be used to do work, such as turn a motor or power a light.

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3 years ago