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Anton [14]
3 years ago
9

How many grams of H2 are needed to react with 2.40 g of N2?

Chemistry
1 answer:
Georgia [21]3 years ago
5 0
Is there an equation? I can't help if there's no equation involved.
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5. You are investigating an arson scene and you find a corpse in the rubble, but you suspect that the victim did not die as a re
Marina CMI [18]

Answer:

See the answer below.

Explanation:

Fire has three major components:

  • Heat
  • Smoke
  • Gases ( in form of CO, CO2 etc)

If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.

If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.

<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>

8 0
2 years ago
Carbon dioxide and water is produced when a hydrocarbon combines with ____________________.
Kaylis [27]
They combine with oxygen atoms, I think.
3 0
3 years ago
Hat do you think it means if something is radioactive?
amm1812

Answer:

The process by which an unstable nucleus emits one or more particles or energy in the form of electromagnetic radiation.

Explanation:

3 0
2 years ago
What is an independent variable
frez [133]

Answer:

a variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

4 0
3 years ago
How many atoms of N are in 137.0 grams of N2O3?
lara [203]

Answer: Option (d) is the correct answer.

Explanation:

It is given that mass of N_{2}O_{3} is 137.0 g.

Molar mass of  N_{2}O_{3} is as follows.

    Molar mass of  N_{2}O_{3} = 2 × 14 + 3 × 16

                                                                = 76 g

Thus, number of moles will be calculated as follows.

        No. of moles = \frac{mass}{molar mass}

                              = \frac{137.0 g}{76 g/mol}

                              = 1.803 mol

There are 2 nitrogen (N) atoms present in the formula of dinitrogen trioxide. Also Avogadro's number equals 6.022 \times 10^{23} atoms or molecules per mol.

Therefore, number of N molecules or atoms in N_{2}O_{3} is as follows.

           Number of N atoms = 2 \times 1.803 mol \times 6.022 \times 10^{23} atoms/mol

                                             = 2 \times 10.855 \times 10^{23} atoms

                                             = 2.171 \times 10^{24} atoms

Thus, we can conclude that there are 2.171 \times 10^{24} atoms of N in in 137.0 grams of N_{2}O_{3}.

6 0
3 years ago
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