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3 years ago

Which one requires more work walking 1 mile running 1 mile

Physics

1 answer:

Andre45 [30]3 years ago

8 0

Answer:

running does

Explanation:

your using more muscells and breathing heavy

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(PLEASE HELP) In a solution such as salt water, the component that does the dissolving is called the

Delicious77 [7]

Answer:

B) Solvent

Explanation:

This is because the solute is dissolved in the solvent.

In the example of salt water, the water is the solvent and the salt is the solute.

The solute is substance being dissolved.

The solvent is what the solute is being dissolved in.

7 0

3 years ago

Read 2 more answers

A projectile is launched from ground level with an initial speed of 49.7 m/s. Find the launch angle (the angle the initial veloc

BigorU [14]

Answer: $\theta =75.52^{\circ}$

Explanation:

Given

initial speed of Launch $(u)$ =49.7 m/s

Range of Projectile =Maximum height of Projectile

Range is given by R $=\frac{u^2\sin 2\theta }{g}$

Maximum height is given by $H_{max}=\frac{u^2\sin ^2\theta }{2g}$

$R=H_{max}$

$\frac{u^2\sin 2\theta }{g}=\frac{u^2\sin ^2\theta }{2g}$

$\frac{u^2\sin 2\theta }{g}-\frac{u^2\sin ^2\theta }{2g}=0$

$\frac{u^2\sin \theta }{g}\cdot \left [ 2\cos \theta -\frac{1}{2}\right ]=0$

as u cannot be zero therefore

$2\cos \theta -\frac{1}{2}=0$

$\cos \theta =\frac{1}{4}$

$\theta =75.52^{\circ}$

8 0

4 years ago

Describe at least three ways that you can make the ball look red.

Zarrin [17]

Answer:

color it heat it and thats it oh yeah and paint

3 0

3 years ago

Is this charging by induction or conduction?

sineoko [7]

Conduction i believe

3 0

3 years ago

Suppose that you make a series RC circuit with a capacitor and a known resistor that has a 5% tolerance: R= 5.20 ± 0.26kΩ. You p

Masja [62]

Answer:

correct answer is C

Explanation:

The time constant of an RC circuit is

τ = RC

so to find the capacitance

C = τ/ R

C = 2.150 / 5.20 10³

C = 4.13 10⁻⁴ F

to find the error we use the worst case

ΔC = | $|\frac{dC}{d \tau }| \ \Delta \tau + | \frac{dC}{dR} | \ \Delta R$

the absolute value guarantees that we find the worst case, we evaluate the derivatives

ΔC = 1 /R Δτ + τ/R² ΔR

the absolute values of the errors are

Δτ = 0.002 s

ΔR = 0.3 kΩ

we substitute

ΔC = 0.002 /5.20 10³ + 2.150/(5.20 10³)² 0.3 10³

ΔC = 3.8 10⁻⁷ + 1.74 10⁻⁵

ΔC = 1.77 10⁻⁵ F

the uncertainty or error must be expressed with a significant figure

ΔC = 2 10⁻⁵ F

the percentage error is

Er% = $\frac{\Delta C}{C} \ 100$

Er% = $\frac{2 \ 10^{-5} }{ 4.13 \ 10^{-4} } \ 100$

Er% = 4.8%

the correct answer is C

3 0

3 years ago