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Marianna [84]
3 years ago
14

Was the significant digits convention indicative of your uncertainty in the measurements above

Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer: Yes, the significant digits convention was indicative of your uncertainty in the measurements.

Concept:

<u><em>Significant Figures:</em></u> In the measured value of a physical quantity, the number of digits about the correctness of which we are sure plus the next doubtful digit, are called Significant Figures.

There are certain values of physical quantities which are defined; like irrational numbers ∛2, √3, the speed of light ( 299792458... m/s), converted value of centimeter in to inches (2.54...), the refractive index of the glass with respect to the water ( 1.333....) etc. These values are defined but they have no limit of significant figures because we can consider the measurement up to any extent which differ from the measurement to the measurement.

Hence, the significant digits convention always gives the uncertainty in the measurements.

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Calculate the density of Saturn. Show your work. How does it compare with the density of water? Explain how this can be.
stepladder [879]

Answer:

The density of Saturn is 686.81 kg/m³.

Explanation:

Mass of Saturn,  m=5.68\times 10^{26}\ kg  

Volume of Saturn, V=8.27\times 10^{23}\ m^3

Density of Saturn is given by its mass divided by its volume i.e.

d=\dfrac{m}{V}

d=\dfrac{5.68\times 10^{26}}{8.27\times 10^{23}}

d=686.81\ kg/m^3

So, the density of Saturn is 686.81 kg/m³.

The density of water is 1000 kg/m³. It is clear that the density of Saturn is less than water.

4 0
3 years ago
The image shows a model of the gravitational field around Earth. Which best describes the model?
GuDViN [60]

<u>Answer: The model is described by :</u>

The strength of the field increases as you get closer to Earth, as shown by the smaller spaces between the circles.

Explanation :

According to universal gravitational law, the force acting in the universe between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}

It is clear that the gravitational force depends directly on the product of masses and inversely on the square of the distance between them.

The given image shows a model of the gravitational field around Earth. The arrows in the image show the direction of the force. Gravitational field depends on the position of objects.

As we move closer to the earth, the force increases and hence the field increase.

So, the correct option is (D) " The strength of the field increases as you get closer to Earth, as shown by the smaller spaces between the circles ".

3 0
4 years ago
Read 2 more answers
Which freezes faster, hot water or cold water?
Digiron [165]
Hot water<span> seems to </span>freeze faster<span> than </span>cold water<span>, known as the Mpemba effect. The effect was named after the Tanzanian student who in 1963 noticed that </span>hot<span> ice cream mix </span>freezes faster<span> than a </span>cold<span> one. hope this helped</span>
8 0
3 years ago
Read 2 more answers
Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of
Alchen [17]

Answer:

\theta=10.20^{\circ}  

\Delta l=0.10 ft    

Explanation:

First of all, we analyze the system of blocks before starting to move.

\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0  

\Sum F_{x}=11sin(\theta)+5sin(\theta)-0.16N_{A}-0.23N_{B}=0

11sin(\theta)+5sin(\theta)-0.16P_{A}cos(\theta)-0.23P_{B}cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0  

16sin(\theta)-2.91cos(\theta)=0  

tan(\theta)=0.18  

\theta=arctan(0.18)  

\theta=10.20^{\circ}  

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.  

P_{A}sin(\theta)-F_{fA}-F_{spring}=0

Where:

F_{spring} = k\Delta l=2.1\Delta l

P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0

\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}

\Delta l=0.10 ft    

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

4 0
3 years ago
An object with more inertia is both harder to _____ and to _______ ...?
Aleks [24]
An object with more inertia is both harder to start and to stop. <span>The heavier (or more mass) of the object - harder to start & stop. For instance, a large rock vs. small rock. Large rock harder to get rolling & harder to stop as compared to smaller rocks. Hope this answers the question.</span>
4 0
3 years ago
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