Answer:
The people with caculators will probably answer faster due to thier ablitiy to use a device of technology
Answer:
Explanation:
The electric force between two charged objects is given by:
where:
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is their separation
In this problem:
q1 = 2.0 C
q2 = 1.0 C
r = 2 m
So, the electric force is
Answer:
For an excellent understanding of the system, we must first consider that everything that all the objects within it are at rest, which implies directly that the initial moment is zero.
From this it is logical to intuit that when applying an external force on the system, the speed of the system will be generated to change.
Thus applying the law of conservation, we understand that
Initial System Moment = Final System Moment.
From this we conclude that the final moment is 0.
Momentum = 0kg-m / s
Answer:
The speed of the clay before the impact was 106.35 m/s.
Explanation:
the only force doing work on the system is the frictional force, f, the work done by f is given by:
Wf = ΔK = Kf - Ki
The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:
f×Δx = Ki
m×g×Δx×μ = 1/2×m×v^2
v^2 = 2×g×Δx×μ
= 2×(9.8)×(7.50)×(0.650)
= 95.55
v = 9.78 m/s
This is the veloty of clay and block after the clay hit the block.
if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:
m×v1 +M×V = v(m + M)
m×v1 = v(m + M)
v1 = v(m + M)/m
v1 = (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)
v1 = 106.35 m/s
Therefore, the speed of the clay before the impact was 106.35 m/s.
