1) D
2) D.) Greater than 
Explanation:
1)
The phenomenon of total internal reflection occurs when a ray of light hitting the interface between two mediums is totally reflected back into the original medium, therefore no refraction into the second medium occurs.
This phenomenon occurs only if two conditions are satisfied:
- The index of refraction of the first medium is larger than the index of refraction of the 2nd medium
- The angle of incidence is greater than a certain angle called critical angle
In picture 1, we have 4 different diagrams. In the diagrams:
- The red arrow represents the incident ray
- The green arrow represents the refracted ray
- The blue arrow represents the reflected ray
Total internal reflection occurs when there is no refraction, therefore when there is no green arrow: this occurs only in figure D, so this is the correct option. (in figure C, there is a refracted ray but it is parallel to the interface: this condition occurs when the angle of incidence is exactly equal to the critical angle, however in this problem, the angle of incidence is greater than the critical angle, so the correct option is D)
2)
As we stated in problem 1), total internal reflection occurs when the angle of incidence is equal or greater than the critical angle. Therefore in this case, the angle of incidence must be
D.) Greater than
Answer:B
Explanation: an atom is the smallest particle of an element that can take part in a chemical reaction.
We have a wave function: D(y,t) and we want to know some things about it. 1. The direction the wave is travelling is negative y direction or -y. 2. Since sound waves are longitudinal waves, this sound wave is oscillating along the y axis. 3. The wavelength we can get from k=2π/λ, k is the wave number, λ is the wavelength. So λ=2π/k=6.28/8.96=0.7 m. 4. Before i get the wave speed i will calculate the period of oscillation. It can be calculated from: ω=2πf where ω is angular frequency and f is wave frequency. So f=ω/2π=3140/6.28=500 Hz and the period is T=1/f=1/500=0.002 s. 5. Wave speed is v=λ*f= 0.7*500=350 m/s.
Answer:
T₁= 75.25 N : Wire tension forming angle of 52° with horizontal
T₂ = 60.49 N : Wire tension forming angle of 40° with horizontal
Explanation:
We apply Newton's first law to the holiday decoration in equilibrium
Forces acting on holiday decoration:
T₁ : Wire tension forming angle of 52° with horizontal
T₂ : Wire tension forming angle of 40° with horizontal
W= m*g= 10 kg*9.8 m/s² = 98 N : weight of the decoration
∑Fx=0
T₁x -T₂x = 0
T₁x = T₂x
T₁*cos52° = T₂*cos40°
T₁= T₂*(cos40°) / (cos52°)
T₁= 1.244T₂ Equation (1)
∑Fy=0
T₁y+T₂y -W = 0
T₁*sin52° + T₂*sin40° - 98 = 0 Equation (2)
We replace T₁ of the equation (1) in the equation (2)
1.244T₂*sin52° + T₂*sin40° - 98 = 0
0.98T₂ + 0.643T₂ = 98
1.62T₂ = 98
T₂ = 98 / 1.62
T₂ = 60.49 N
We replace T₂ = 60.49 N in the Equation (1)
T₁= 1.244*60.49 N
T₁= 75.25 N
