Answer:
In its simplest form the domain is all the values that go into a function, and the range is all the values that come out.
Step-by-step explanation:
In a right triangle, the measure of one acute angle is 30 less than twice the measure of the other acute angle. Find the measure of each angle.
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The sum of the 2 acute angles is 90 degrees.
x + y = 90
x = 2y-30
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Substitute for "x" and solve for "y":
2y-30 +y = 90
3y = 120
y = 40
x = 90-y
x = 90-40
x = 50
Answer: Because the a-value is negative.
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k where
- "a" is the vertical stretch
- -a is a reflection over the x-axis
- h is the horizontal shift (positive = right, negative = left)
- k is the vertical shift (positive = up, negative = down)
Given: g(x) = - (x + 1)² - 3
↓
a= -1
Since the a-value is negative, the parabola will be reflected over the x-axis which will change the curve from (U-shaped) to (∩-shaped).
C) reflection over the x-axis
Answer: The area of the path is 280 ft^2
(Note that 280 ft^2 means “280 feet squared”)
Step-by-step explanation: The first clue in this question is the dimensions of the rectangular garden which have been given as 29 ft by 37 ft. So we can conveniently compute the area of the garden as follows;
Area = L x W
(Length is 37 ft and Width is 29 ft)
Area = 37 x 29
Area = 1037 ft^2
However there is a path surrounding the garden which is 2 ft wide on all four sides. This means both borders of the length have an extra 4 feet of measurement while both borders of the width also have an extra 4 feet of measurement. So, if the surrounding border and garden is measured altogether, the length would become (37 + 4= 41) 41 feet while the width would become (29 + 4 = 33) 33 feet. So the area of the garden and the surrounding path inclusive can be calculated as
Area = L x W
Area = 41 x 33
Area = 1353 ft^2
To determine the area of ONLY THE SURROUNDING PATH, we simply deduct the area of the GARDEN ONLY (1073 ft^2) from the area of GARDEN AND SURROUNDING PATH (1353 ft^2)
Therefore area of the path surrounding the garden becomes
Area of path = 1353 - 1073
Area of path = 280 ft^2
