The planes speed would be 560 miles/hour.
If you divide 3360 by 6 = 560
In 10 hours the plane would travel 5,600 miles.
560 x 10 = 5600
simplify
n-2 = 10n/2 + 4/2
n-2 = 5n + 2
subtract 5n to both sides
n - 2 - 5n = 5n + 2 - 5n
simplify
-4n - 2 = 2
add 2 to both sides
-4n - 2 + 2 = 2 + 2
simplify
-4n = 4
divide both sides by -4
-4n/-4 = 4/-4
simplify
n = -1
hope it helps
Round 28 to nearest ten and 868 to nearest hundred
900 ÷ 30 = 30
The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
