Answer:
Area of the figure = 31.25π cm²
Perimeter of the figure = (12.5π + 10) cm
Step-by-step explanation:
Area of the given figure = Sum of area of the two semicircle + area of a quarter circle
Area of one quarter circle (CDE) = 
= 
= 6.25π
Area of one semicircle = 2 × Area of one quarter circle
= 2(6.25π)
= 12.5π
Area of the given figure = 2×12.5π + 6.25π
= 25π + 6.25π
= 31.25π cm²
Perimeter of the figure = Perimeter of two semicircles + perimeter of one quarter circle + measure of radius DE + measure of radius AB
Perimeter of one semicircle = πr
= 5π cm
Perimeter of one quarter circle = 2.5π
Perimeter of the complete figure = 10π + 2.5π + 5 + 5
= (12.5π + 10) cm
Answer:
C) 9
Step-by-step explanation:
The response is very low
Answer:
Mean : 95
Median : 85
Mode : 90
Part B : Impossible
Step-by-step explanation:
We can make an equation to find the mean using the first 5 history test scores.

So a 95 would be needed to have a mean of 85.
Next, the median.
First, we sort the first 5 history scores from least to greatest.
We get 75, 75, 80, 90, 95.
Since, 80 is the middle value, it will be used in the calculation of the median.
We can make an equation with this.

So a score a 85 would be needed to have a median of 82.5
Thirdly, the mode.
Since 90 is already in the set once, we can just have Maliah score another 90 to make 90 the mode (with the exception of 75 of course).
Finally, Part B.
We can use the equation we had for the first mean calculation but change 85 to 90.

So Maliah would need a score of 125 to make her mean score 90, but since the range is only from 0-100, it is impossible.
Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0
5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2
The solution to the problem is as follows:
If you use Ln you can get rid of e.
ln(e^0.4x) = ln(0.4)
0.4x = ln(0.4)
x = (ln(0.4))/0.4
<span>x = -2.29
</span>
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