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katrin [286]
3 years ago
8

8.5b−3.4∙(13a−3.2b)+a

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

8.5b - 3.4(13a - 3.2b) + a = 19.4b - 43.2a

Step-by-step explanation:

It is a simple mathematical problem with multiple like terms. We can solve it by applying basic mathematical rules of multiplication and addition/subtration.

8.5b - 3.4(13a - 3.2b) + a

= 8.5b - 3.4*13a -3.4*(-3.2b) + a

= 8.5b - 3.4*13a + 3.4*3.2b + a

= 8.5b - 44.2a + 10.88 b + a

Now, only like terms can be added to each other

= (8.5b + 10.9b) + (a - 44.2a)

= 19.4b + (-43.2a)

= 19.4b - 43.2a    

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Some examples:

* An elevator can only hold 50 people at maximum. Therefore, x can be any number smaller than 50 or 50 itself. Having 51 or over will be too much.

* You can only work 50 hours for one stretch of some 2 week period. If x is the number of hours you work, then x must be 50 or less as written by x \le 50. So x could be x = 37 as it's less than 50, but x = 62 is not possible.

* For some small ride at a theme park, the seats are designed such that only people 50 inches or less can ride on them. If x is the height of a person in inches, then x \le 50 means something like x = 37 is possible but x = 62 is too high.

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3 years ago
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7 0
3 years ago
5x+2y=-3;x+5y=4<br>plz answer me​
Alex17521 [72]

Answer:

x = -1 and y = 1

Step-by-step explanation:

5x + 2y = -3 . . . . . . . (i)

x + 5y = 4 . . . . . . . (ii)

  • Finding x in terms of y from eq. (ii) :-

x + 5y = 4

x = 4 - 5y

  • Placing this value of x in eq. (i) :-

5(4 - 5y) + 2y = -3

20 - 25y + 2y = -3

-23y = - 23

<u>y = 1</u>

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5x + 2(1) = -3

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7 0
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Read 2 more answers
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Marrrta [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Which of the following is the equation of a hyperbola with center at (0, 0), with a = 4, b = 1, opening horizontally?
matrenka [14]

Answer:

The equation of the hyperbola is x²/16 - y²/1 = 1

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the x-axis is

  x²/a² - y²/b² = 1

# The length of the transverse axis is 2a

# The coordinates of the vertices are (±a , 0)

# The length of the conjugate axis is 2b

# The coordinates of the co-vertices are (0 , ±b)

# The coordinates of the foci are (± c , 0),  

# The distance between the foci is 2c where c² = a² + b²

* Now lets solve the problem

∵ The center of the hyperbola is (0 , 0)

∵ It is opening horizontally

∴ x²/a² - y²/b² = 1

∵ a = 4 , b = 1

∴ a² = (4)² = 16

∴ b² = (1)² = 1

∴ x²/16 - y²/1 = 1

∴ The equation of the hyperbola is x²/16 - y²/1 = 1

6 0
2 years ago
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