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3 years ago

15

Help with a pre-calc question? I'll mark the Brainliest if you explain your answer.

1 answer:

anzhelika [568]3 years ago

3 0

Answer:

It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.

Step-by-step explanation:

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51 participants went on the 7th grade field trip to the national history museum.2/3 of them rode on a large bus.The rest went in

labwork [276]

51 ÷ 3 = 17
17 were in the van
51 - 17 = 34
34 were in the bus

3 0

3 years ago

Read 2 more answers

6x - 8 ≤ 184 <br> i need answer for test corrections

jekas [21]

I hope this helps.....

Explanation:
I took this in 9th grade so I know how to do this kind of stuff

5 0

2 years ago

Find the distance between the two points and simplest rational form (3,-4) (6,-7))

pychu [463]

Answer:

$D = 3\sqrt{2}$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,-4)$

$(x_2,y_2) = (6,-7)$

Required

Determine the distance between the two points

Distance (D) is calculated as:

$D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute values for x's and y's

$D = \sqrt{(6 - 3)^2 + (-7 - (-4))^2}$

$D = \sqrt{(6 - 3)^2 + (-7 +4)^2}$

$D = \sqrt{(3)^2 + (-3)^2}$

$D = \sqrt{9+9}$

$D = \sqrt{18}$

Express as 9 * 2

$D = \sqrt{9*2}$

Split:

$D = \sqrt{9}*\sqrt{2}$

$D = 3*\sqrt{2}$

$D = 3\sqrt{2}$

4 0

2 years ago

This net can be folded to make a square pyramid. what is the surface area of the pyramid

givi [52]

Answer:

$85in^2$

Step-by-step explanation:

to find the surface area we need to find the followng areas:

area of the square

area of a triangle and multiply it by 4 (because there are 4 triangles)

And once we have those areas, we add them to find the surface area.

Area of the square:

the formula to find the area of a square is:

$a_{square}=l^2$

where $l$ is the length of the side: $l=5in$

thus the area of the square is:

$a_{square}=(5in)^2$

$a_{square}=25in^2$

Area of the triangles:

the are of 1 triangle is given by

$a_{triangle} =\frac{b*h}{2}$

where $b$ is the base of the triangle: $b=5in$ (the base of the triangle is the side of the square)

and $h$ is the height of the triangle: $h=6in$

thus, the area of 1 triangle is:

$a_{triangle} =\frac{(5in)*(6in)}{2}$

$a_{triangle} =\frac{30in^2}{2}$

$a_{triangle} =15in^2$

the area of the 4 triangles is (we multiply by 4):

$a_{4-triangles}=4(15in^2)$

$a_{4-triangles}=60in^2$

finally we add the area of the square and the area of the 4 triangles to find the total surface area:

$Surface=25in^2+60in^2$

$Surface=85in^2$

8 0

2 years ago

PLEASE SEE THE ABOVE PICTURE.<br><br>Solve this part please fast<br>Give the right answers <br><br>

galina1969 [7]

Step-by-step explanation:

believe it or not, the area of any triangle is

baseline × height / 2

we have here 2 triangles, both with the same baseline (8 cm), but with 2 different heights : 6.5 cm and 4.6 cm.

so, their areas are

8 × 6.5 / 2 = 4 × 6.5 = 26 cm²

8 × 4.6 / 2 = 4 × 4.6 = 18.4 cm²

so, in total, the shaded region is

26 + 18.4 = 44.4 cm²

8 0

2 years ago