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luda_lava [24]
3 years ago
15

Help with a pre-calc question? I'll mark the Brainliest if you explain your answer.

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.

Step-by-step explanation:

You might be interested in
the perimeter of an equilateral triangle is 63 inches. if the length of each side is (4x-3), find the value of x
Ber [7]
Use the equation 4x-3=63
4 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} - 14
s344n2d4d5 [400]

Answer:

Factorized

      =(2x-8)(x-3)

Roots : 4 , 3

Step-by-step explanation:

If it is to factorize :

2x^2 - 14x + 24 = 2x^2 -6x-8x +24

                     =2x(x-3)-8(x-3)\\=(2x-8)(x-3)

If it is to solve for x :

2x^2 -1 4x + 24 = 0\\(2x-8)(x-3)=0\\2x - 8 = 0 \ , \ x - 3 = 0\\2x = 8 \ , \ x = 3\\x = 4 , 3

6 0
3 years ago
A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height​ h, in​ feet, after t seconds is
olchik [2.2K]
Check the picture below.

thus is at 0 = -16t² + 96t +640,

\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)&#10;\\\\\\&#10;0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=&#10;\begin{cases}&#10;\boxed{10}\\&#10;-4&#10;\end{cases}

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0
4 years ago
2x²-5x-12=0 (simplify solution set)
Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

ax^2+bx+c=0

Let's find a, b, c:

  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}

x=\frac{5\pm\sqrt{121} }{4}

x=4 or x=\frac{-3}{2}

<u />

<u>Answer:</u>

x = 4 or x = -3/2

7 0
2 years ago
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