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neonofarm [45]
3 years ago
11

How many reflectional symmetries does a regular decagon have ?

Mathematics
2 answers:
blagie [28]3 years ago
7 0
I believe the answer is 5
pentagon [3]3 years ago
6 0
The answer to this is ten.

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Look at the rectangle and the square: Ada says that the length of diagonal SQ is two times the length of diagonal OM. Is Ada cor
Musya8 [376]

Answer:

No, she is wrong.

Step-by-step explanation:

A diagonal of square or rectangle is equals to hypotenuse of a triangle. So you can apply Pythagoras Theorem to solve it :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Rectangle,

{qs}^{2}  =  {rs}^{2}  +  {qr}^{2}

{qs}^{2}  =  {16}^{2}  +  {8}^{2}  = 320

qs =  \sqrt{320}  = 17.9 \: inches

Square,

{om}^{2}  =  {lo}^{2}  +  {lm}^{2}

{om}^{2}  =  {8}^{2}  +  {8}^{2}  = 128

om =  \sqrt{128}  = 11.3 \: inches

Given that QS is 17.9 and OM is 11.3. So SQ is not 2 times greater than OM.

17.9 \div 11.3 = 1.58 \: (not \: equals \: to \: 2)

7 0
2 years ago
Question / Of 9
mario62 [17]

Answer:

i was gonna answer this but im

im late :(

Step-by-step explanation:

4 0
3 years ago
On Saturday, 4 groups of people went to the restaurant at the ski resort. Each group had 5 people in it. Everyone ordered a cup
VMariaS [17]

Answer: 23 cups

Step-by-step explanation:

There were 4 groups with 5 people each and all of them ordered a cup of hot chocolate:

= 4 * 5

= 20 cups

Rebecca, Malaki, and Jeffrey each ordered an extra cup of hot chocolate so that's 3 extra cups:

= 20 + 3

= 23 cups

4 0
3 years ago
Factorise the expression 3a2-4ab as far as possible
horsena [70]
In this case, you have to find a common multiple of 3a^2 and 4ab. As only one of the numbers is divisible by two, this means that two cannot go outside of the bracket. The only other aspect that is in both sides of the equation is a, therefore, this goes outside the bracket. The best way to approach this is to divide both sides by a, and this will give you what is inside the bracket. 3a^2 divided by a is 3a, therefore, this is the first aspect in the bracket. -4ab divided by a, leaves -4b. Therefore, these go in the bracket.
3a^2- 4ab simplified is a(3a-4b)
Hope this helps 
7 0
2 years ago
Butter kruse made 522 glaze donuts and 323 chocolate covered donuts. They put the donuts in boxes. Each box holds 12 donuts. How
il63 [147K]

Answer:

71 boxes

Step-by-step explanation:

1. Add 522 (# of glaze donuts) and 323(# of chocolate covered donuts).....845(# of total donuts)

2. Divide 845 by 12(the # of donuts each box could hold)....70.41666(repeating)

3. As you can't have a 0.41666 of a box, you round up 70.4166666 to 71.

71*12=852 70*12=840

Even though 71 boxes is more than enough to hold 845 donuts, there is simply no other choice, as there is no smaller box that holds less than 12 donuts.

7 0
2 years ago
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