Answer:
<u>Is "y (x-4) squared +6": y = (x-4)^2 + 6?</u>
If so,
<u>x = y^(1/2) - 6^(1/2) + 4</u>
Step-by-step explanation:
<h2><u>
Assuming the equation is: y= (x-4)^2 + 6</u></h2>
y^(1/2)= (x-4) + 6^(1/2)
(x-4) = y^(1/2) - 6^(1/2)
x = y^(1/2) - 6^(1/2) + 4
V of cylinder = πr²h
h=V /(πr²)
h=27/π -exact value
h=1323/(3.14*(7)²)= 8.6 cm - approximate value
Answer: x-9
Step-by-step explanation: You can rewrite that to get 4/3x-1/3x-5-4
That simplifies to x-9
Easy
if x is the number
sqrt x is between 17 and 18
17<√x<18
squaer the whole thing
289<x<324
x could be 300
it could be sqrt of 300
√300=10√3
one is 10√3