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4 years ago

A perfect square is a number that has an integer square root True or false

Mathematics

2 answers:

Sati [7]4 years ago

8 0

This is true.
These are perfect squares: 4, 9, 25. These are not: 7, 8, 11

mylen [45]4 years ago

7 0

Answer:

its true on apex .

Step-by-step explanation:

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Find the solution of given expression !!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B36%20%5Ctimes%204%7D%20" id="TexF

Law Incorporation [45]

$\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}$

Let's Solve :

$\sqrt{36 \times 4}$

$\sqrt{2 \times 2 \times 3 \times 3 \times 2 \times 2}$

$2 \times 3 \times 2$

$12$

Therefore, the correct answer is 12

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$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

6 0

3 years ago

Suppose when solving a system of linear equations in two variables, both variables happen to cancel, leaving you with a false st

miss Akunina [59]

Step-by-step explanation:

C. The system of equations is unsolvabl

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3 years ago

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I need assistance solving these questions using Cramers' Rule (which I am frankly terrible at) and need these to finish my homew

Scrat [10]

Answer:

What are the questions?

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3 years ago

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Item 19 Question 1 A furniture store is having a sale where everything is 40% off. a. Write a function that represents the amoun

astraxan [27]

Whatever% of anything is just (whatever/100) * anything.

therefore, if an item has been discounted by 40%, the discounte is that 40%, what is 40% of the price "p"? (40/100) * p or 0.4p.

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3 0

4 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

3 years ago