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3 years ago

What is the sum of r+s, when r = –14.1 and s = 18.3?

1 answer:

5 0

$Subtitute\ the\ values\ of\ r=-14.1\\and\ s=18.3\ to\ the\ expression\ r+s:\\\\r+s=-14.1+18.3\\---------\\use\ commutative\ property:a+b=b+a\\\----------\\\\=18.3+(-14.1)=18.3-14.1=\huge\boxed{4.2}$

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The equations y = (- 16t - 2)(t - 1) and y = - 16t ^ 2 + 14t + 2 represent the height in feet of a beach ball thrown by a child

KatRina [158]

Answer:

0.4375secs

Step-by-step explanation:

Given the height of the beach ball in feet expressed as;

y = -16t^2+14t+2 as the height that represents the height of the ball, we can look for the time taken by the ball to reach its maximum height

At the max height, the velocity is zero i.e dt/dt = 0

dy/dt = -32t + 14

0 = -32t + 14

32t = 14

t = 14/32

t = 0.4375secs

Hence it took the ball 0.4375secs to reach its maximum height

5 0

3 years ago

What are the zeros of the polynomial function

aliya0001 [1]

Answer:

Step-by-step explanation:

F(x) = x^3 - 5x^2 - 6x

F(x)=x(x^2-5x-6)

F(x)=x(x-6)(x+1)

So, x=0,-1,6

6 0

4 years ago

Find the area bounded by the given curves: y=2x−x2,y=2x−4

Andrej [43]

Answer:

$A = [\frac{32}{3}]$

Step-by-step explanation:

Given

$y_1 = 2x - x^2$

$y_2 = 2x - 4$

Required

Determine the area bounded by the curves

First, we need to determine their points of intersection

$2x - x^2 = 2x - 4$

Subtract 2x from both sides

$-x^2 = -4$

Multiply through by -1

$x^2 = 4$

Take square root of both sides

$x = 2$ or $x = -2$

This Area is then calculated as thus

$A = \int\limits^a_b {[y_1 - y_2]} \, dx$

Where a = 2 and b = -2

Substitute values for $y_1$ and $y_2$

$A = \int\limits^a_b {(2x - x^2) - (2x - 4)} \, dx$

Open Brackets

$A = \int\limits^a_b {2x - x^2 - 2x + 4} \, dx$

Collect Like Terms

$A = \int\limits^a_b {2x - 2x- x^2 + 4} \, dx$

$A = \int\limits^a_b {- x^2 + 4} \, dx$

Integrate

$A = [-\frac{x^{3}}{3} +4x](2,-2)$

$A = [-\frac{2^{3}}{3} +4(2)] - [-\frac{-2^{3}}{3} +4(-2)]$

$A = [-\frac{8}{3} +8] - [-\frac{-8}{3} -8]$

$A = [\frac{-8+ 24}{3}] - [\frac{8}{3} -8]$

$A = [\frac{-8+ 24}{3}] - [\frac{8-24}{3}]$

$A = [\frac{16}{3}] - [\frac{-16}{3}]$

$A = [\frac{16}{3}] + [\frac{16}{3}]$

$A = [\frac{16 + 16}{3}]$

$A = [\frac{32}{3}]$

Hence, the Area is:

$A = [\frac{32}{3}]$

7 0

4 years ago

Y is inversely proportional to x . When y = 25 , x = 4 Work out y when x = 20

ehidna [41]

Answer: 125

Step-by-step explanation:

4/25 = 20/Y

Cross multiply to get the equation

4Y = 500

Divide both sides by 4

Y=125

7 0

3 years ago

How many solutions are there for the pair of equations for lines Q and S? Explain your answer.

krek1111 [17]

No solution because the lines are parallel.

7 0

3 years ago

Read 2 more answers