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love history [14]
3 years ago
7

If one factor of x2 + 2x - 24 is (x+6), what is the other factor?

Mathematics
1 answer:
Anni [7]3 years ago
4 0

Answer:

(x - 4)

Step-by-step explanation:

Given

x² + 2x - 24

Consider the factors of the constant term (- 24) which sum to give the coefficient of the x- term (+ 2)

The factors are + 6 and - 4, since

6 × - 4 = - 24 and 6 - 4 = + 2, thus

x² + 2x - 24 = (x + 6)(x - 4) ← in factored form

Thus the other factor is (x - 4)

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Explain how you could mentally find 8 x 45 by using the distributive property
dangina [55]
First, break up 45 into 40 and 5 then multipy 8(40) which equals 320 and multipy 8(5) which equals 40. Thrn add 320+40 to get the product 360.
Hope this helped

8x45
8(40)+8(5)
320+40
360
6 0
4 years ago
Write an equation passing through the point and perpendicular to the given line: (-3,5);y = 3/4x-4
balandron [24]

Hey!

So the first thing we realize is that it says that the equation is perpendicular to the line, meaning that the slope of the line is the negative reciprocal of the slope of the line you are given. Since we are given the slope of this line as 3/4 we can take the negative reciprocal of this to get -(4/3).

Now that we have the slope and a point on the line you can plug those into the equation y = mx + b to find b. The slope of the line is m and the point contains the x and y values.

5 = -(4/3)(-3) + b

5 = 4 + b

1 = b

Since we have the y-intercept and the slope now we can plug that into the slope-intercept form equation to get the equation we need:

y = -(4/3)x + 1

7 0
3 years ago
If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

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