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3 years ago

Need help what is the answer and what is the equation

Mathematics

1 answer:

My name is Ann [436]3 years ago

5 0

10 degrees Celsius is 50 degrees Fahrenheit.
The equation for C to F is below.
C(9/5)+32= F
Multiply C by 1.8 (or 9/5) then add 32.
10(9/5)+32= 50 F

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Read 2 more answers

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

Area of polygon D = 10 square units

Step-by-step explanation:

Given:

Polygon C has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

To find:

The area of polygon D = ?

Solution:

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides 6, 8 and 10 units.

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = 10 sq units

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3 years ago

What is sum of -3x^2 - 7x + 9 and - 5x^2 + 6x - 4

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2 years ago

The volume V of a solid right circular cylinder is given by V = πr2h where r is the radius of the cylinder and h is its height.

emmainna [20.7K]

Answer:

8.20in³

Step-by-step explanation:

Given V = πr²h

r is the radius = 1.5in

h is the height = 6in

thickness of wall of the cylinder dr = 0.04in

top and bottom thickness dh 0.07in+0.07in = 0.14in

To compute the volume, we will find the value of dV

dV = dV/dr • dr + dV/dh • dh

dV/dr = 2πrh

dV/dh = πr²

dV = 2πrh dr + πr² dh

Substituting the values into the formula

dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14

dV = 2π (0.36)+π(1.89)

dV = 0.72π+1.89π

dV = 2.61π

dV = 2.61(3.14)

dV = 8.1954in³

Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)

7 0

3 years ago