A. that is b^2-4ac
for
ax^2+bx+c
the deterimant (part under the radicand)
is b^2-4ac
if it is
1. less than 0 then there are no real solutions
2. eqal to 0 then there is 1 real solution
3. greater than 0, there are 2 real roots
9x^2-16x+60
b^2-4ac=(-16)^2-4*9*60=256-2160<0
no real solutions
B. grouping
ac method
4 times -5=-20
what 2 numbers multiply to get -20 and add to get 8?
-2 and 10
seperate the middle number to get that
4x^2-2x+10x-5=0
(4x^2-2x)+(10x-5)=0
2x(2x-1)+2(2x-1)=0
(2x-1)(2x+2)=0
set equal to 0
2x-1=0
2x=1
x=1/2
2x+2=0
2x=-2
x=-1
x=1/2 or -1
is the equation
Basically, you are multiplying 1.8 and 8.4 by itself ten times but here is a tip:
When multiplying by ten, move the decimal once to the right
So
and
That leaves
which is
Answer: 102
Answer:
kpl- 90°
jpk-52°
npm-142°
lpm-38°
Step-by-step explanation:
Answer:
subtract 61 from 90
Step-by-step explanation:
thatb will be your answer
