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vitfil [10]
3 years ago
8

If the​ length, width, and height of a cube all change by a factor of 7​, what happens to the volume of the​ cube?

Mathematics
1 answer:
Mkey [24]3 years ago
4 0

9514 1404 393

Answer:

  The volume is 343 times as large.

  The length is 7 times as large.

Step-by-step explanation:

If the original cube has side length s, its volume is given by ...

  V = s³

When the side length is changed by a factor of 7, the new volume is ...

  V = (7s)³ = 7³×s³ = 343s³

The volume of the cube changes by a factor of 7³ = 343.

__

The problem statement tells you the length is 7 times as large.

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The perimeter of a rectangular field is 328 yards. If the length of the field is 89 yards, what is its width?
miv72 [106K]

<u>Set up an equation based on the information given</u>

89 + 89 + x + x = 328

<u>Combine like terms</u>

89 + 89 = 178

x + x = 2x

2x + 178 = 328

<u>Solve</u>

2x + 178 = 328

328 - 178 = 150

2x = 150

x = 75

Answer

The width of the rectangular field is 75 yards.

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Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using
AlladinOne [14]

Answer:

<u></u>

  • <u>a) P(X=1) = 0.302526</u>
  • <u>b) P(X=5) = 0.010206</u>
  • <u>c) P(X=3) = 0.18522</u>
  • <u>d) P(X≤3) = 0.92953</u>
  • <u>e) P(X≥5) = 0.010935</u>
  • <u>f) P(X≤4) = 0.989065</u>

Explanation:

Binomial experiments are modeled by the formula:

       P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}

Where

  • P(X=x) is the probability of exactly x successes

  • C(n,x)=\dfrac{n!}{x!\cdot (n-x)!}

  • p is the probability of one success, which must be the same for every trial, and every trial must be independent of other trial.
  • n is the number of trials
  • 1 - p is the probability of fail
  • there are only two possible outcomes for each trial: success or fail.

<u>a.) P (x=1)</u>

<u></u>

       P(X=1)=\dfrac{6!}{1!\cdot (6-1)!}\times (0.3)^1\times(1-0.3)^{(6-1)}=0.302526

<u>b.) P (x=5)</u>

     P(X=5)=\dfrac{5!}{5!\cdot (6-5)!}\times (0.3)^5\times (1-0.3)^{(6-5)}=0.010206

<u>c.) P (x=3)</u>

Using the same formula:

    P(X=3)=0.18522

<u>d.) P (x less than or equal to 3)</u>

  • P(X≤3)= P(X=3) + P(X=2) + P(X=1) + P(X=0)

Also,

  • P(X≤3) = 1 - P(X≥4) = 1 - P(X=4) - P(X=5) - P(X=6)

You can use either of those approaches. The result is the same.

Using the second one:

  • P(X=4) = 0.059335
  • P(X=5) = 0.010206
  • P(X=6) = 0.000729

  • P(X≤3) = 1 - 0.05935 - 0.010206 - 0.000729 = 0.92953

<u>e.) P(x greather than or equal to 5)</u>

  • P(X≥5) = P(X=5) + P(X=6)
  • P(X≥5) = 0.010206 + 0.000729 =  0.010935

<u>f.) P(x less than or equal 4)</u>

  • P(X≤4) = 1 - P(X≥5) = 1 - P(X=5) - P(X=6)
  • P(X≤4) = 1 - 0.010206 - 0.000729 = 0.989065
5 0
3 years ago
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