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2 years ago

If the length, width, and height of a cube all change by a factor of 7, what happens to the volume of the cube?

Mathematics

1 answer:

Mkey [24]2 years ago

4 0

9514 1404 393

Answer:

The volume is 343 times as large.

The length is 7 times as large.

Step-by-step explanation:

If the original cube has side length s, its volume is given by ...

V = s³

When the side length is changed by a factor of 7, the new volume is ...

V = (7s)³ = 7³×s³ = 343s³

The volume of the cube changes by a factor of 7³ = 343.

The problem statement tells you the length is 7 times as large.

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Enter the slope of the line through the points (5, 2) and (-3, -7).

ehidna [41]

Answer:

m=9/8 or 1 1/8

Step-by-step explanation:

m= change in y over change in x

2 - -7 = 9

5 - -3 = 8

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2 years ago

Im turning percents into fractions and im not sure how to do this one please help

slava [35]

4 1/7 = (4*100) +(1/7 of 100)= (400+ 14.28)= 414.28

The answer is 414.28

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2 years ago

Murphy loves pistachio nuts. Every saturday morning, she walks to the market and buy some. Last week, she bought two pounds and

Alexxx [7]

Question is Incomplete, Complete question is given below,

Murphy loves pistachio nuts. Every Saturday morning, she walks to the market and buys some. Last week, she bought two pounds and paid $7.96, and this week she bought only one-half pound and paid $1.99. What the unit rate for pistachio nuts?

Answer:

The unit rate for pistachio nuts is $3.98.

Step-by-step explanation:

Given;

Price of 2 pounds of pistachio nuts = $7.96

We need to find the price of 1 pound of pistachio nuts.

To find the same we will use the unitary method,

Hence ,

Price of 1 pound of pistachio nuts = $\frac{\$7.96}{2} = \$3.98$

Also given:

Price of half pound of pistachio nuts = $1.99

We need to find the price of 1 pound of pistachio nuts.

To find the same we will use the unitary method,

Hence ,

Price of 1 pound of pistachio nuts = $\$1.99\times 2 = \$3.98$

Hence, The unit rate for pistachio nuts is $3.98

3 0

3 years ago

Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas

Vitek1552 [10]

Answer:

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0

2 years ago

I don't get how to work out the repeating problems, could someone explain please?

barxatty [35]

Detecting...

Your answer would be:

$0.025 = 1/40 

0.025/1 * 1000/1000 = 25/1000

25 \div 25 / 1000 \div 25 = 1/40

1/40 is your answer.$

3 0

2 years ago

If the​ length, width, and height of a cube all change by a factor of 7​, what happens to the volume of the​ cube?

If the length, width, and height of a cube all change by a factor of 7, what happens to the volume of the cube?