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Bas_tet [7]
3 years ago
11

Two factors of 24 add up to 11. What are they?​

Mathematics
2 answers:
Georgia [21]3 years ago
8 0

ANSWER

My answer is in the photo above

Readme [11.4K]3 years ago
6 0

Answer:

The numbers are 8 and 3.

Step-by-step explanation:

Let a and b the numbers.

If a and b are factors of 24, then ab = 24

If a and b has to add up to 11, the a +b = 11

Solving for a in terms of b in the equation, a +b = 11:

a +b = 11 \\ a +b -b = 11 -b \\ a = 11 -b

Solving the equation ab = 24 by plugging in a:

ab = 24 \\ (11 -b)b = 24 \\ -b^2 +11b = 24 \\ b^2 -11b = -24 \\ b^2 -11b +\frac{121}{4} = -24 +\frac{121}{4} \\ (b -\frac{11}{2})^2 = -\frac{96}{4} +\frac{121}{4} \\ (b -\frac{11}{2})^2 = \frac{25}{4} \\ \sqrt{(b -\frac{11}{2})^2} = \pm \sqrt{\frac{25}{4}} \\ b -\frac{11}{2}= \pm \frac{5}{2}

Solving b from the positive root:

b -\frac{11}{2} +\frac{11}{2} = \frac{5}{2} +\frac{11}{2} \\ b = \frac{16}{2} \\ b = 8

Solving b from the negative root:

b -\frac{11}{2} +\frac{11}{2} = -\frac{5}{2} +\frac{11}{2} \\ b = \frac{6}{2} \\ b = 3

Solving for a in the equation, a = 11 -b when b = 3:

a = 11 -(3) \\ a = 11 -3 \\ a = 8

Solving for a in the equation a = 11 -b when b = 8:

a = 11 -(8) \\ a = 11 -8 \\ a = 3

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