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____ [38]
3 years ago
6

What is the quotient?

Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0

Answer:

= \dfrac{1}{5^{9}}

Step-by-step explanation:

When dividing values with exponents, we simply need to subtract the numerators exponent to the denominators exponent.

So we have:

\dfrac{5^{-6}}{5^{3} }

= 5^{-6 - 3}

= 5^{-9}

Now since we have a negative exponent, we can get the reciprocal of the value to make it positive.

= \dfrac{1}{5^{9}}

r-ruslan [8.4K]3 years ago
3 0

Answer:

The answer is 1 / 5^(9)

Step-by-step explanation:

We just need to divide both numbers and find the result

(5)^-6 / (5)^3

(5)^(-6-(3)) =

(5)^(-9) =

1 / 5^(9) = 5,120 .10^(-7)

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Answer:

Instead of moving the 3x to the opposite side of the equation they moved the 2x. And the correct answer is x=-6 not x=6.

Step-by-step explanation:

Student Work:

2(x + 4) – 8 = 3x+10-4

2x + 8–8 = 3x + 6

2x = 3x + 6

- 3x – 3x

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My work:

2(x+4)-8=3x+10-4

2x+8-8=3x+6

2x=3x+6

-x=6

x=-6

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3 years ago
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7 0
4 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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ruslelena [56]
The coorect answer is C. 1, 2, 5, 10
8 0
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