When solving these proportions we just remember when moving a number from one side to the other if it started in the numerator it ends up in the denominator and vice versa.

I'll do it in two steps here for teaching purposes; it's not too hard to go directly to the answer.

$\dfrac{13}{7} = \dfrac{10}{v}$

$13 v = 7(10)$

$v= \dfrac{7 \cdot 10 }{13} = \dfrac{70}{13} \approx 5.4$

5 0

3 years ago

Read 2 more answers

Prove that

Dovator [93]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = $\frac{1}{cosx}$ , cosecx = $\frac{1}{sinx}$

cotx = $\frac{cosx}{sinx}$ , tanx = $\frac{sinx}{cosx}$

Consider the left side

secA cosecA - cotA

= $\frac{1}{cosA}$ × $\frac{1}{sinA}$ - $\frac{cosA}{sinA}$

= $\frac{1}{cosAsinA}$ - $\frac{cosA}{sinA}$

= $\frac{1-cos^2A}{cosAsinA}$

= $\frac{sin^2A}{cosAsinA}$ ( cancel sinA on numerator/ denominator )

= $\frac{sinA}{cosA}$

= tanA = right side ⇒ proven

5 0

3 years ago

Find the quotient of 4.13 x 10^-8 and 0.04 x 10^5. In two or more complete sentences, explain each step in your calculations.Inc

poizon [28]

we know that

Quotient is the number resulting from the division of one quantity by another

Let

x--------> the first quantity

y------> the second quantity

q------> the quotient

$q=\frac{x}{y}$ -------> equation 1

in this problem

$x=4.13*10^{-8} \\ y= 0.04*10^{5}$

Substitute the values in the equation 1

$q=\frac{4.13*10^{-8}}{0.04*10^{5}}$

Simplify

$q=\frac{4.13*10^{-8}}{0.04*10^{5}}=\frac{4.13}{0.04}*10^{-8}*10^{-5}=\frac{4.13}{0.04}*10^{-13}\\ \\q=103.25*10^{-13}\\ \\q= (1.0325*10^{2})*10^{-13}\\ \\q= 1.0325*10^{-11}$

therefore

<u>the answer is</u>

The quotient is equal to $1.0325*10^{-11}$

6 0

3 years ago

Two times a number plus six is eight

AleksandrR [38]

Answer:

Why:

2 × 1 + 6

2 + 6 = 8

8 0

3 years ago