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katrin2010 [14]

2 years ago

15

TODAY IS MY BIRTHDAY everyone send some kind works I just turned 12

2 answers:

My name is Ann [436]2 years ago

8 0

Answer:

happy birthday

Step-by-step explanation:

have a great day

alukav5142 [94]2 years ago

7 0

Congratulations - 12 is an awesome age! Happy Birthday!

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Blueberry high-fiber muffins contain 51 % dietary fiber by mass. If a package with a net weight of 18 oz contains six muffins, h

8_murik_8 [283]

Answer:

In each muffin there are 1.53oz

Step-by-step explanation:

The first step is to get the weight of just one muffin. If the package contains six muffins we must divide the total weight by six.

$weight_{unit}=\frac{18oz}{6}=3oz$

The weight of just one muffin is 3oz.

Now, the problem says that blueberry high-fiber muffins contain 51 % dietary fiber by mass, which means that we must calculate the 51% of 3oz. We must take into account that 51% equals 51/100 which is 0.51. The equation would be:

$fiber=(3oz)(0.51)=1.53oz$

Finally, in each muffin there are 1.53oz of fiber.

6 0

3 years ago

A committee consisting of4 faculty members and 5 students is to be formed. Every committee position has the same duties and voti

tigry1 [53]

Answer:

More than 1 committee can be formed, *1 and a half<em>*</em>

5 0

3 years ago

Solve the given proportion.<br><br> x = [?]

Readme [11.4K]

Answer:

x=48

Step-by-step explanation:

I hope I helped!!1

6 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

㏒₅(x+4)+㏒₅(x+1)=2 solved

balu736 [363]

Answer:

x= $\frac{-5+\sqrt{109} }{2}$

or dec. is x= 2.72

8 0

3 years ago

Read 2 more answers