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Tamiku [17]
3 years ago
5

PLEASEEEEEEE HELP ME!

Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

DC = 6

Step-by-step explanation:

Given in the question,

radius = 3x

tangents to the circle = 12 + 5x and 8 + 7x

If you draw line from A to D, two right angle triangle will be form ADC and ADB

having radius  = 3x

<h3>By using pythagorus theorem</h3><h3>hypotenuse² = base² + height²</h3><h3 />

Since, both triangle share same hypotenuse AD

so,

<h3>     ΔADC                        ΔADB</h3><h3>base² + height² = base² + height²</h3><h3 />

3x² + (8 + 7x)² = 3x²  + (12 + 5x)²

3x² will be cancel out

(8 + 7x)² =  (12 + 5x)²

64 + 112x + 49x² = 144 + 120x + 25x²

rearranging like terms

49x²-25x² +112x - 120x + 64 -144 = 0

24x² - 8x - 80 = 0

(x- 2)(x + 5/3)

x = 2

x = -5/3 rejected as radius can't be negative

So,

length of radius = 3x = 6

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Answer:

5x=55

Divide both sides by 5 to solve for x

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How is the graph of y=2(3)^x+1 translated from the graph of y = 2(3)^x
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y=2(3)x

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Find the smallest value of k, such that 16k is a perfect cube.
zimovet [89]

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Solve the system below using substitution write your final answer as a coordinate point
Mademuasel [1]

(3, -2)

Step-by-step explanation:

y = -2x + 4

-x + 3y = -9

-x + 3 (-2x + 4) = -9

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We substitute x with 3 to evaluate y;

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Elimination Method;

y = -2x + 4

-x + 3y = -9

We arrange the equations for substitution;

2x + y = 4

-x + 3y = -9

We multiply the first equation with 3 so we can substract one variable to zero;

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6x + 3y = 12

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(3, -2)

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